Answer: The critical value for a two-tailed t-test = 2.056
The critical value for a one-tailed t-test = 1.706
Step-by-step explanation:
Given : Degree of freedom : df= 26
Significance level : 
Using student's t distribution table , the critical value for a two-tailed t-test will be :-

The critical value for a two-tailed t-test = 2.056
Again, Using student's t distribution table , the critical value for a one-tailed t-test will be :-

The critical value for a one-tailed t-test = 1.706
Hello user
To solve for V we simplify both sides of the equation then isolate the variable to get v <span>≥ 2
Therefor the answer is: </span>v ≥ 2
<span>
I hope this helped
-Chris</span>
Answer:
3×5×53
Step-by-step explanation:
You can use divisibility rules to find the small prime factors.
The number ends in 5, so is divisible by 5.
795/5 = 159
The sum of digits is 1+5+9 = 15; 1+5 = 6, a number divisible by 3, so 3 is a factor.
159/3 = 53 . . . . . a prime number,* so we're done.
795 = 3×5×53
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* If this were not prime, it would be divisible by a prime less than its square root. √53 ≈ 7.3. We know it is not divisible by 2, 3, or 5. We also know the closest multiples of 7 are 49 and 56, so it is not divisible by 7. Hence 53 is prime.
Step-by-step explanation:

Hence, base = 2 units and hypotenuse = 3 units.





Now, we know that :


Therefore, the required answer is 3/√5.
Answer:
0.5
Step-by-step explanation:
We are looking for how much height is gained per cup added.
Height per cup added can be calculated by finding the slope of the line that runs through the two given points on the graph, (3, 5.5) and (8, 8).
Formula for slope =
Let,