A.) y = ut - 1/2gt^2 + 12
y = 6t - 1/2(9.8)t^2 + 12
y = 6t - 4.9t^2 + 12
b.) The y-intercept is 12
c.) The y-intercept represent the height of the ball at time t = 0
d.) At the time the ball reaches the ground, y = 0
-4.9t^2 + 6t + 12 = 0
t = 2.29 seconds
Therefore, it took the ball 2.29 seconds to reach the ground.
Answer:
12 and 8
Step-by-step explanation:
set two numbers as x and y
mean of 10 → x+y/2=10
range of 4 → x-y=4
x+y=20
+ x-y=4
____________
2x=24, x=12
12-y=4, y=8
Answer:
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Step-by-step explanation:
