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stealth61 [152]
3 years ago
7

Solve the system of linear equations using elimination. −2x − y = 3 −9x − y = 17

Mathematics
2 answers:
Gnom [1K]3 years ago
4 0

Answer: x=20/7 y=17

Step-by-step explanation:

1) Don't need to solve for y since y is already solved.

2) Solve for x:

-2x-17=-9x+3

-2x-17+9x=-9x+3+9x (Add 9x to both sides)

7x-17=3

7x-17+17=3+17 (Add 17 to both sides)

7x=20( Divide both sides by 7)

x=20/7, y=17

Nat2105 [25]3 years ago
4 0

Answer:

x=20/7 y=17

Step-by-step explanation:

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The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti
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Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

P(t)=10000(0.2)^t

1) P(0) is the population initially.

P(1) is the population after a year.

\frac{P(1)}{P(0)} represents the population increase factor.

So let's evaluate that fraction:

\frac{P(1)}{P(0)}

\frac{10000(0.2)^1}{10000(0.2)^0}

\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

P(t)=10000(0.2)^{t}

We want t to represent months.

A full year is 12 months, in a full year we have that P(1)=10000(0.2)^1=10000(0.2)=2000

So we want a new P such that P(12)=2000 since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) P(12)=10000(0.87449)^{12}=2000 \text{approximately}

b) P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}

c) P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}

d) P(12)=10000(0.87449)^{12+12}=400 \text{approximately}

So a is the function we want.

Also another way to look at this:

P(t)=10000(.2)^t where t is in years.

P(t)=10000(.2^\frac{1}{12})^t where t is in months.

And .2^\frac{1}{12}=0.874485 \text{approximately}

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