3 years ago

What would x any y be? Simply your answer pls

Mathematics

1 answer:

Helen [10]3 years ago

5 0

Look it up on google

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Three pirates named Ahab sparrow and Davy play a game. The pirates have total of 210 coins, and each pirate has a different numb

nignag [31]

No of coins Sparrow had in the beginning 92 coins

Step-by-step explanation:

Total coins = 210

Current ratio = 4:5:6

It implies 210 needs to be split into 15 parts (4+5+6)

So, each part = 210/15 = 14 coins

Again which implies 14*4 : 14*5 : 14*6 = 56 : 70 : 84

So before the game began,

No of coins Ahab had = (56 - 5) = 51

No of coins Davy had = (84 - 7) = 67

Hence, No of coins Sparrow had = (210 - 51 - 67) = 92 coins

8 0

3 years ago

Find all critical values of the function g(x)=5/(x²-x+6)

Sati [7]

$g(x)=\frac{5}{x^2-x+6}\\\\D:x^2-x+6\neq0\\\\\Delta=(-1)^2-4\cdot1\cdot6=1-24=-23 < 0\\\\x\in\mathbb{R}\\\\vertex\ of\ y=x^2-x+6\\\\p=\frac{-(-1)}{2\cdot1}=\frac{1}{2}\\\\q=\frac{-(-23)}{4\cdot1}=\frac{23}{4}\\\\\lim\limits_{x\to\frac{1}{2}}\frac{5}{x^2-x+6}=\frac{5}{\frac{23}{4}}=\frac{5\cdot4}{23}=\frac{20}{23}$

$\lim\limits_{x\to\pm\infty}\frac{5}{x^2-x+6}=0$