3 years ago

Why is hydrogen peroxide sold in opaque plastic bottles?

Chemistry

1 answer:

allochka39001 [22]3 years ago

4 0

it's not a very stable compound

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24. The air in a small 250 cm birthday balloon is at a pressure of 760 torr. A boy sits on it at

kvv77 [185]

Answer:

1.14atm

Explanation:

Given parameters:

V1 = 250cm³ ;

1000cm³ = 1dm³; so this is 0.25dm³

P1 = 760torr

760torr = 1atm

V2 = 220cm³ ; 0.22dm³

Unknown:

New pressure = ?

Solution:

To solve this problem, we apply Boyle's law and we use the expression below:

P1 V1 = P2V2

The unknown is P2;

1 x 0.25 = P2 x 0.22

P2 = 1.14atm

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3 years ago

The website of a popular stargazers club notes that on Wednesday the moon will rise at 6:23 PM and set at 6:12 PM on Thursday. W

astraxan [27]

It's C that's correct because it's very true...

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3 years ago

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I have no idea on how to do this here is the question (For the following pairs of atoms, show how they transfer valence electron

Maru [420]

Answer:

uhh

Explanation:

i hope you find this answer

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3 years ago

7. A small stone added to boiling liquids to make them boil more evenly without sudden violent releases of

Rzqust [24]

Answer:

A boiling chip, boiling stone, porous bit or anti-bumping granule is a tiny, unevenly shaped piece of substance added to liquids to make them boil more calmly.

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3 years ago

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A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following

marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

$\frac{V_1}{n_1} =\frac{V_2}{n_2}$

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

$\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}$

V₂ = 4,00L

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

$\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}$

V₂ = 16,00L

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

$\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}$

V₂ = 12,31L

I hope it helps!

6 0

4 years ago