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Katyanochek1 [597]
4 years ago
12

What is the main intermolecular force in H2CO?

Chemistry
1 answer:
aivan3 [116]4 years ago
5 0
Dipole-dipole interactions, and London dispersion interactions
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Give the answer to the problem below using the correct number of significant digits. (1.3 x 103) x (5.724 x 104)
Gemiola [76]
(133.9) x (595.296)= 79,710.1344
Answer with significant digits: 80,000
1.3 has two significant digits so 79,700 rounds up to 80000.
6 0
3 years ago
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Dalton's law of partial pressures states that the total pressure exerted by a mixture of gases is the sum of the pressures exert
Damm [24]

Answer: The given statement is true.

Explanation:

According to the Dalton's law, total pressure of a mixture of gases that do not react with each other is equal to the partial pressure exerted by each gas.

The relationship is as follows.

          p_{total} = \sum_{i=1}^{n} p_{i}

or,        p_{total} = p_{1} + p_{2} + p_{3} + p_{4} + ......... + p_{n}

where,  p_{1}, p_{2}, p_{3} ....... = partial pressure of individual gases present in the mixture

Also, relation between partial pressure and mole fraction is as follows.

                 p_{i} = p_{total} \times x_{i}

where,      x_{i} = mole fraction

Thus, we can conclude that the statement Dalton's law of partial pressures states that the total pressure exerted by a mixture of gases is the sum of the pressures exerted independently by each gas in the mixture, is true.              

5 0
3 years ago
The sum of the protons and neutrons in an atom is called the atomic number <br> True or False
olganol [36]
It is false, the atomic number is the number of protons and/or electrons in an atom on an element.
3 0
3 years ago
_Cl2 + _NaBr → _NaCl + _Br2<br><br> Answer: 1,2,2,1
nlexa [21]
1 2 2 1 is the answer so u are correct
4 0
3 years ago
Identify the oxidizing agent and the reducing agent for 4Li(s) + O_2 (g) to 2Li_2O(s).
wolverine [178]

Answer: Li is the reducing agentg and O is the oxidizing agent.

Explanation:

1) The oxidizing agent is the one that is reduced and the reducing agent is the one that is oxidized.

2) The given reaction is:

4Li(s) + O₂ (g) → 2 Li₂O(s)

3) Determine the oxidation states of each atom:

Li(s): oxidation state = 0 (since it is alone)

O₂ (g): oxidation state = 0 (since it is alone)

Li in Li₂O (s) +1

O in Li₂O -2

That because 2× (+1) - 2 = 0.

4) Determine the changes:

Li went from 0 to + 1, therefore it got oxidized and it is the reducing agent.

O went from 0 to - 2, therefore it got reduced and it is the oxidizing agent.

7 0
4 years ago
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