All categories

3 years ago

I need help with this solving equations X + 9 = -16

Mathematics

2 answers:

Jlenok [28]3 years ago

8 0

Answer:

X= -25

Step-by-step explanation:

Subtract 9 from both sides.

Wittaler [7]3 years ago

7 0

Answer:

Step-by-step explanation:

x + 9 = -16

Subtract 9 form both sides

x + 9 - 9 = - 16 - 9

x = -25

You might be interested in

Expand the expression 2(r - 4) + 5(r + 2). Express your answer in simplest form

Andrews [41]

$2(r - 4) + 5(r + 2) =2r-8+5r+10=7r+2$

6 0

3 years ago

Read 2 more answers

What are the points for this?

Marrrta [24]

Answer:

Step-by-step explanation:

8 0

3 years ago

a video game has 35 levels in it if you beat 5 of the levels what is the ratio of levels left to the levels that have been beate

lesantik [10]

Answer: 30:5

Step-by-step explanation:

Five levels were beaten so thirty levels are left so whats left to what’s beaten is 30:5

7 0

3 years ago

The function f (x comma y )equals 3 xy has an absolute maximum value and absolute minimum value subject to the constraint 3 x sq

zmey [24]

Answer:

The maximum value of f is 363, which is reached in (11,11) and (-11,-11) and the minimum value of f is -33, which is reached in (√11,-√11) and (-√11,√11)

Step-by-step explanation:

f(x,y) = 3xy, lets find the gradient of f. First lets compute the derivate of f in terms of x, thinking of y like a constant.

$f_x(x,y) = 3y$

In a similar way

$f_y(x,y) = 3x$

Thus,

$\nabla{f} = (3y,3x)$

The restriction is given by g(x,y) = 121, with g(x,y) = 3x²+3y²-5xy. The partial derivates of g are

[ŧex] g_x(x,y) = 6x-5y [/tex]

$g_y(x,y) = 6y - 5x$

Thus,

$\nabla g(x,y) = (6x-5y,6y-5x)$

For the Langrange multipliers theorem, we have that for an extreme (x0,y0) with the restriction g(x,y) = 121, we have that for certain λ,

$f_x(x_0,y_0) = \lambda \, g_x(x0,y0)$
$f_y(x_0,y_0) = \lambda \, g_y(x_0,y_0)$
$g(x_0,y_0) = 121$

This can be translated into

$3y = \lambda (6x-5y)$
$3x = \lambda (-5x+6y)$
$3 (x_0)^2 + 3(y_0)^2 - 5\,x_0y_0 = 121$

If we sum the first two expressions, we obtain

$3x + 3y = \lambda (x+y)$

Thus, x = -y or λ=3.

If x were -y, then we can replace x for -y in both equations

3y = -11 λ y

-3y = 11 λ y, and therefore

y = 0, or λ = -3/11.

Note that y cant take the value 0 because, since x = -y, we have that x = y = y, and g(x,y) = 0. Therefore, equation 3 wouldnt hold.

Now, lets suppose that λ=3, if that is the case, we can replace in the first 2 equations obtaining

3y = 3(6x-5y) = 18x -15y

thus, 18y = 18x

y = x

and also,

3x = 3(6y-5x) = 18y-15x

18x = 18y

x = y

Therefore, x = y or x = -y.

If x = -y:

Lets evaluate g in (-y,y) and try to find y

g(-y,y) = 3(-y)² + 3y*2 - 5(-y)y = 11y² = 121

Therefore,

y² = 121/11 = 11

y = √11 or y = -√11

The candidates to extremes are, as a result (√11,-√11), (-√11, √11). In both cases, f(x,y) = 3 √11 (-√11) = -33

If x = y:

g(y,y) = 3y²+3y²-5y² = y² = 121, then y = 11 or y = -11

In both cases f(11,11) = f(-11,-11) = 363.

We conclude that the maximum value of f is 363, which is reached in (11,11) and (-11,-11) and the minimum value of f is -33, which is reached in (√11,-√11) and (-√11,√11)

5 0

3 years ago

What is the algebraic expression for the following word phrase: the product of 5 more than p and 7?

lisabon 2012 [21]

Answer: Option 'B' is correct.

Step-by-step explanation:

Since we have given that

"The product of 5 more than p and 7"

1) 5 more than p is written as

$p+5$