1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tema [17]
4 years ago
11

what could one do to harvest the truffula trees to make all of the tree products but ensure there would be trees for the future?

Biology
1 answer:
cricket20 [7]4 years ago
5 0
Plant the seeds after they cut them my dood. thanks for the points.
You might be interested in
Is water wet. Yes or NO.
Alecsey [184]
Yes. Hope this helps
6 0
3 years ago
Read 2 more answers
uppose that molecules of glucose are ingested, absorbed into the bloodstream, and then converted inside muscle cells to carbon d
Sophie [7]

Answer:

Phase 1: Preparation, regulation and energy expenditure

In the initial preparatory phase of glycolysis (investment phase), glucose is phosphorylated twice by ATP and cleaved into two phosphate trioses. [2] At this stage, the cell spends two molecules of ATP, the Mg2 + cation is indispensable for the reactions, and five biochemical reactions are processed. No energy is stored, on the contrary, two ATP molecules are invested in phosphorylation reactions.

Reaction 1: hexokinase

In the first reaction, the glucose entering the tissues is phosphorylated to the hydroxyl group at C6, with the energy expenditure of an ATP molecule, giving rise to glucose-6-phosphate and ADP. [1] This reaction, catalyzed by the hexokinase enzyme, is irreversible under physiological conditions due to its highly negative ΔG °. It is one of the three steps that regulate glycolysis. The phosphorylation of glucose in the first reaction prevents it from leaving the cell again (glycolysis takes place in the cell's cytosol). By adding a phosphate group to glucose, it becomes a negatively charged molecule and it is impossible to passively pass through the cell membrane, keeping it trapped within the cell.

Glucose-6-phosphate is a branching point in carbohydrate metabolism. It is a precursor to almost all routes that use glucose, including glycolysis, via pentose phosphate and glycogen synthesis. From an opposite point of view, it can also be generated from other carbohydrate metabolism routes, such as glycogenolysis (glycogen breakdown), via pentose phosphate and gluconeogenesis (synthesis of glucose from non-carbohydrates).

Hexokinases, enzymes that catalyze glucose phosphorylation, are a family of tissue-specific isoenzymes that differ in their kinetic properties. The isoenzyme found in the liver and cells of the pancreas has a much higher Km than other hexokinases and is called glycokinase. Kinases are enzymes that catalyze the transfer of a terminal phosphoryl group from ATP to a nucleophile acceptor. In the case of hexokinase, the acceptor is a hexose, usually D-glucose, although hexokinase can catalyze the phosphorylation of other common hexoses, such as D-fructose and D-mannose. Hexokinase, like many other kinases, requires Mg2 + for its activity, since the true substrate of the enzyme is not ATP-4, but MgATP-2. In many cells, part of the hexokinase is bound to porins in the outer mitochondrial membrane, which give these enzymes early access to the newly synthesized ATP as it leaves the mitochondria.

Reaction 2: phosphohexose isomerase

In the second reaction, catalyzed by the enzyme glycosphosphate isomerase (also called phosphoxose isomerase), glucose-6-phosphate, an aldose, is converted into a reversible isomerization process in fructose-6-phosphate, a ketosis, thus allowing a site input for dietary fructose in glycolysis. This isomerization plays a critical role in the general chemistry of the glycolytic pathway, since the rearrangement of the carbonyl and hydroxyl groups at C-1 and C-2 is a necessary preparation for the next two steps. The phosphorylation that occurs in the next reaction (reaction 3) requires that the group at C-1 be first converted from a carbonyl to an alcohol and, in the subsequent reaction (reaction 4), the cleavage of the bridge between C-3 and C-4 by aldolase requires a carbonyl group at C-2.

Reaction 3: phosphofructokinase-1 (PFK1)

In reaction number 3, the cell invests another ATP molecule to phosphorylate fructose-6-phosphate and convert it to fructose-1,6-bisphosphate. This is also an irreversible and control reaction of this metabolic pathway, catalyzed by the enzyme phosphofrutokinase, which is the enzyme pacemaker of glycolysis. This step occurs to make the molecule symmetrical for the cleavage reaction in the next step.

Reaction 4: aldolase

In reaction 4, fructose-1,6-bisphosphate is cleaved into two trioses: glyceraldehyde-3-phosphate and dihydroxyacetone phosphate. This reaction is catalyzed by the enzyme aldolase.

Reaction 5: triosphosphate isomerase

Glyceraldehyde-3-phosphate and dihydroxyacetone phosphate are isomers that are easily interconnected by the enzyme triosphosphate isomerase. Then, the conversion of dihydroxy ketone P into glyceraldehyde 3P occurs, the only triosis that can continue to be oxidized.

Phase 2: ATP production and oxidation

In the ATP generation phase (yield), glyceraldehyde-3-phosphate (a phosphate triosis) is oxidized by NAD and phosphorylated using inorganic phosphate. The high-energy phosphate bridge generated in this step is transferred to the ADP to form ATP. The remaining phosphate is also rearranged to form another high-energy phosphate bridge that is transferred to the ADP. As there are two moles of phosphate triosis formed, the result

Explanation:

5 0
3 years ago
Explain why the marine ecosystem generates a significant fraction of the oxygen in the atmosphere. A) The marine ecosystem gener
Nat2105 [25]

Answer:

The organisms in the marine ecosystem converts carbon dioxide to oxygen faster than organisms in other ecosystems.

Explanation:

Simply the organism in the ecosystem seaweed and phytoplanktons makes use of CO2, water, and sunlight to synthesize foods for energy production.During this processes, O2 is liberated as by products from the photolysis of water. These marine photsynthesizers  ensures abundant supply of oxygen to the atmosphere.

7 0
3 years ago
In a population of humans, the frequency of straight hair is 34 percent. If straight hair is the recessive phenotype, what is th
MatroZZZ [7]

34 percent  fam  I saw it on quizlet  fyi thats where I get my answers and help on my work


3 0
3 years ago
Read 2 more answers
To become a virus, you only need 2 parts. One is Genetic Material or Genome (DNA or RNA) to
Naya [18.7K]

Answer: true

Explanation:

7 0
4 years ago
Other questions:
  • . Explain how the structure of the plasma membrane makes it selectively permeable. What kinds of substances can pass through the
    12·1 answer
  • Genetic tendencies shape the environments to which people are exposed during life. nature shapes nurture through both _____ and
    13·1 answer
  • Consider the following claim: Group behavior can increase the chances for an individual and a species to survive and reproduce.
    8·1 answer
  • The central nervous system includes...
    10·2 answers
  • The doctor said "The child is you, simply the best of you." What does this mean?
    10·1 answer
  • Structures in plant leaves open and close to maintain homeostasis are called
    5·1 answer
  • What will most likely happen to the genetic diversity in the population over time
    13·1 answer
  • I will mark correct answer brainliest
    10·2 answers
  • I’ll mark as BRANLIEST!!<br><br> 30 POINTS!!<br><br> Please help me!!
    7·1 answer
  • Chloroplasts and mitochondria are both involved in energy conversion in cells and share many similarities. Differentiate between
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!