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alex41 [277]
3 years ago
9

Consider the piecewise-defined function given by the graph. What are these values?

Mathematics
2 answers:
maksim [4K]3 years ago
6 0

Answers:

f(-3) = -1

f(-1) = 2

f(3) = 5

======================================

Explanations:

Draw a vertical line through -3 on the x axis. Make sure this vertical line crosses the orange graph. Mark this point of intersection and then draw a horizontal line from this point to the y axis. You should find that it touches -1 on the y axis. Check out the attached image to see this process in action.

Those steps basically say that x = -3 leads to y = -1. Since y = f(x), this means f(-3) = -1

Through similar steps, you should find that f(-1) = 2 and f(3) = 5

Note that the open hole/circle does not count. So if you land on an open hole, just keep going until you hit a closed circle on the other piece of the graph.

Luda [366]3 years ago
3 0

A) f (–3) = -1

B) f (–1) = 2

C) f (3) = 5

<h3>Further explanation </h3>

Straight-line equations are mathematical equations that are described in the plane of cartesian coordinates

General formula

<h3>y-y1 = m (x-x1) </h3>

or

y = mx + c

Where

m = straight-line gradient which is the slope of the line

x1, y1 = the Cartesian coordinate that is crossed by the line

c = constant

The formula for a gradient (m) between 2 points in a line

m = Δy / Δx

or we can use:

\rm \dfrac{y-y_1}{y_2-y_1}=\dfrac{x-x_1}{x_2-x_1}

Piecewise Functions: functions that have different equations based on the input (x) value

We look for 3 pieces of function from the graph

1. graph 1 is a straight line that passes through 2 points : (-4.0) and (-1, -3) so that the straight line equation:

\rm \dfrac{y-0}{-3-0}=\dfrac{x+4}{-1+4}\\\\\dfrac{y}{-3}=\dfrac{x+4}{3}\\\\3y=-3(x+4)\\\\3y=-3x-12\\\\y=-x-4\Rightarrow \:for\:x

2. graph 2 is a straight line with the equation: \

\rm y=2\Rightarrow \:for\:-1\leq x

3. graph 1 is a straight line that passes through 2 points,  (3.5) and (5.1) so that the straight line equation  :

\rm \dfrac{y-5}{1-5}=\dfrac{x-3}{5-3}\\\\\dfrac{y-5}{-4}=\dfrac{x-3}{2}\\\\2(y-5)=-4(x-3)\\\\2y-10=-4x+12\\\\2y=-4x+22\\\\y=-2x+11\:\Rightarrow for\:x\geq   3

A function made up of 3 pieces:

a solid dot means "including",

an open dot means "not including"

\rm y=-x-4\:for\:x

\rm y=2\:for\:-1\leq x

\rm y=-2x+11\:for\:x\geq 3

A) f (–3) =

Because -3 <-1, the function used is y = -x-4, so

f (-3) = - (- 3) -4

f (-3) = 3-4

f (-3) = -1

B) f (–1) =

Because x = -1, the function used y = 2, so

f (-1) = 2

C) f (3) =

Because x = 3, the function used is = -2x + 11, so

f (3) = -2 (3) +11

f (3) = -6 + 11

f (3) = 5

<h3>Learn more </h3>

Piecewise Functions

brainly.com/question/1242635

the inverse of the function

brainly.com/question/628130

domain of the function

brainly.com/question/4135536

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Answer:

x=\frac{-363}{70} ≈ -5.1857

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Step-by-step explanation:

Rewrite the equation system as:

6x+8y=-75

-3x+6y+6z=5

2x-9y=39

Now, write the system in its augmented matrix form:

\left[\begin{array}{cccc}6&8&0&-75\\-3&6&6&5\\2&-9&0&39\end{array}\right]

applying row reduction process to  its associated augmented matrix:

Swap R1 and R3, and then Swap R1 and R2:

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\6&8&0&-75\end{array}\right]

R3+2R1

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\0&20&12&-65\end{array}\right]

3R2+2R1

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&20&12&-65\end{array}\right]

15R3+20R2

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&0&420&1565\end{array}\right]

Now we have a simplified system:

-3x+6y+6z=5\\0-15y+12z=127\\0+0+420z=1565

-3x+6y+6z=5\hspace{5 mm}(1)\\0-15y+12z=127\hspace{3 mm}(2)\\0+0+420z=1565\hspace{3 mm}(3)

From (3):

z=\frac{313}{84} (4)

Replacing (4) in (2)

y=\frac{-192}{35} (5)

Finally replacing (5) and (4) in (1)

x=\frac{-363}{70}

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