Given that Jessica is a custodian at Oracle Arena.
She waxes 20 square meters space of the floor in 5/3 of an hour. Jessica waxes the floor at a constant rate means rate will remain fixed for any hour.
Now we have to find about how many square meters can she wax per hour.
To find that we just need to divide 20 squaer meters by 5/3 hours
=12
Hence final answer is 12 square meters can she wax per hour.
Which can also be written as per hour.
Answer:
The equation that matches the function shown is option;
C.
Step-by-step explanation:
The given graph of the function is a sinusoidal graph
The values of 'x' and 'y' coordinates at the maximum, x-intercept and minimum points are given as follows;
x, y
0 0
π 1
2·π 0
3·π -1
4·π 0
We note that sin(π/2) = 1, sin(π) = 0 sin(3·π/2) = -1, and sin(4·π/2) = sin(2·π) = 0
Therefore;
y = the sine of half the x-value
Which is presented as follows;
.
Answer:
steps below
Step-by-step explanation:
3.2.1 AD = DB* sin 2 = DB * sin θ .. DE // AB ∠2= θ ... (1)
By laws of sines: DB / sin ∠5 = x / sin ∠4
∠4 = θ-α ∠5 = 180°-<u>∠1</u>-∠4 = 180°-<u>∠3</u>-∠4 = 180°-(90°-θ)-(θ-α)) = 90°+α
DB = (x*sin ∠5)/sin (θ-α)
= (x* sin (90°+α)) / sin (θ-α)
AD = DB*sinθ
= (x* sin (90°+α))*sinθ / sin (θ-α)
= x* (sin90°cosα+cos90°sinα)*sinθ / sin (θ-α) .... sin90°=1, cos90°=0
= x* cosα* sinθ / sin (θ-α)
3.2.2 Please apply Laws of sines to calculate the length
