Solve the following system of equations.

Mathematics

1 answer:

Andre45 [30]3 years ago

4 0

The answer is (5,-5)

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What is x*x=15? (Basically make an equation that equals up to 15.)

rodikova [14]

Answer:

$\displaystyle \sqrt{15} = x$

Step-by-step explanation:

Be VERY careful. When it write out the equation that way, it will give the speculation of this:

$\displaystyle 15 = x^2$

Now, in this case, since you were extra explanatory about this [what is written in parentheses], two factors I know of that multiply to 15 are these:

** $\displaystyle 15 = 2 \times 7\frac{1}{2}$

I am joyous to assist you at any time. ☺️

3 0

3 years ago

Just do 11 or 12 or both please im really tired and it 1:34 in the morning plz help

kumpel [21]

Answer:

11)(-1)

12)1.7

Step-by-step explanation:

11)y+z/x

(-3)+(-2)/5

(-5)/5

 (-1)

12)x-5z/y

5+5(-2)/(-3)

5+(-10)/(-3)

(-5)/(-3)

1.666

1.7

Hope this helps you

If you have any question just ask me

3 0

2 years ago

Find cotθ, cosθ, and secθ, where θ is the angle shown in the figure.

Darina [25.2K]

Answer:

$\cos( \theta) = \frac{5}{8} \\ {8}^{2} = {5}^{2} + {opp}^{2} \\ {opp}^{2} = 64 - 25 = 39 \\ opp = \sqrt{39} \\ \sin(\theta) = \frac{\sqrt{39}}{8} \\ \tan(\theta) = \frac{ \sqrt{39} }{5} \\ \cot(\theta) = \frac{1}{\tan(\theta)} = \frac{1}{\frac{ \sqrt{39} }{5}} \\ \cot(\theta) = \frac{5}{ \sqrt{39} } \\ \csc( \theta) = \frac{1}{\sin(\theta)} = \frac{1}{\frac{\sqrt{39}}{8}} \\ \csc( \theta) = \frac{8}{ \sqrt{39} } \\ \sec( \theta) = \frac{1}{\cos( \theta) } = \frac{1}{ \frac{5}{8} } \\ \sec( \theta) = \frac{8}{5}$