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svetlana [45]
3 years ago
15

Manny wants to cover the windows in his home with either wood blinds or curtains. He has 35 windows that he would like to cover,

but he only have $2100 to spend. Wood blinds cost $100 per window. Curtains cost $60 per window. Which system of inequality's represents the number of wood blinds, x, and curtains, y, Manny can purchase?
Mathematics
1 answer:
stepladder [879]3 years ago
5 0

Answer:

x + y \leq 35\\\\100x + 60y\leq2100\\\\x\geq 0\\\\y\geq 0

Step-by-step explanation:

Call x the amount of blinds that Manny buys.

Let's call and the amount of curtains that Manny buys

There are only 35 windows, so the number of curtains and windows can not be greater than 35.

x + y \leq 35\\x\geq 0\\y\geq 0

Manny can only spend $ 2100

Then we can represent this by an inequality in the following way.

100x \leq 2100

and

60y\leq 2100

We can write this as a single inequality:

100x +60y \leq2100

Finally, the set of inequalities to model this problem is:

x + y \leq 35\\\\100x + 60y\leq2100\\\\x\geq 0\\\\y\geq 0

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Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol
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Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

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Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

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(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

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Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

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