Question

Multiply each set of numbers and match it with it’s product

Answer 1

Answer:

1. $1. (\frac{5}{16}) (-2) (-4) (\frac{-4}{5})= -2 \\2. (2\dfrac{3}{5}) (\frac{7}{9})=(\frac{91}{45})\\3. (\frac{2}{3})(-4)(9)= -24\\4. (\frac{-3}{4}) (\frac{7}{8})=(\frac{-21}{32})$

Step-by-step explanation:

These are simple multiplication questions of fractions. We multiply numerator with numerators and denominators with denominators. If numerator and denominator is both divisible by same number we can divide them for simplification.

1. $(\frac{5}{16}) (-2) (-4) (\frac{-4}{5})$

$=(\frac{-10}{16}) (-4) (\frac{-4}{5})\\=(\frac{40}{16}) (\frac{-4}{5})\\=(\frac{-160}{80}) \\dividing\,\, numerator\,\, and\,\, denominator\,\, by\,\, 80\,\,\\= -2$

2. $(2\dfrac{3}{5}) (\frac{7}{9})$

Converting mixed form into fraction form,

$=(\frac{13}{5})(\frac{7}{9})$

Multiplying numerators with each other and denominators with each other

$=(\frac{13*7}{5*9})\\=(\frac{91}{45})$

3. $(\frac{2}{3})(-4)(9)$

Multiplying these terms with each other:

$=(\frac{2*-4}{3})(9)\\=(\frac{-8}{3})(9)\\=(\frac{-8*9}{3})\\=(\frac{-72}{3})$

Dividing numerator and denominator with 3

$=-24$ 

$4. (\frac{-3}{4}) (\frac{7}{8})\\=(\frac{-3}{4}) (\frac{7}{8})\\=(\frac{-3*7}{4*8})\\=(\frac{-21}{32})$