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jarptica [38.1K]
4 years ago
15

We were never taught this in class, and I understand it, kind of... but i'm just confused with everything.

Mathematics
1 answer:
GaryK [48]4 years ago
8 0
\bf \cfrac{x^3y}{xy^5}\cdot \cfrac{x^2y^9}{x^8}\implies \cfrac{x^3x^2y^1y^9}{x^1x^8y^5}
\\ \quad \\
\textit{now, using exponent rules, same base, different exponent}
\\ \quad \\
\cfrac{x^{3+2}y^{1+9}}{x^{1+8}y^5}\implies \cfrac{x^5y^{10}}{x^9y^5}\\
----------------------------\\\bf \textit{now, keep in mind that}
\\ \quad \\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad

\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\\ \quad \\
%  negative exponential denominator
a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad 

\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}}
\\ \quad \\
thus\\
----------------------------\\
\bf \cfrac{x^5y^{10}}{x^9y^5}\implies \cfrac{x^5y^{10}}{1}\cdot \cfrac{1}{x^9}\cdot \cfrac{1}{y^5}\implies x^5y^{10}\cdot x^{\boxed{-9}}\cdot y^{\boxed{-5}}
\\ \quad \\
x^5x^{-9}y^{10}y^{-5}\implies x^{5-9}y^{10-5}\implies x^{-4}y^5
\\ \quad \\
\cfrac{1}{x^{\boxed{4}}}\cdot \cfrac{y^5}{1}\implies \cfrac{y^5}{x^4}
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Angle M and angle R are supplementary.
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Step-by-step explanation:

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Suppose x, y and z are integers. Prove that, if 3x−y + 5z is even, then at least one of x, y or z is even.
Elden [556K]

Given:

x, y and z are integers.

To prove:

If 3x-y+5z is even, then at least one of x, y or z is even.

Solution:

We know that,

Product of two odd integers is always odd.          ...(i)

Difference of two odd integers is always even.          ...(ii)

Sum of an even integer and an odd integer is odd.      ...(iii)

Let as assume x, y and z all are odd, then 3x-y+5z is even.

3x is always odd.          [Using (i)]

5z is always odd.          [Using (i)]

3x-y is always even.       [Using (ii)]

(3x-y)+5z is always odd.       [Using (iii)]

3x-y+5z is always odd.

So, out assumption is incorrect.

Thus, at least one of x, y or z is even.

Hence proved.

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The price of a DVD is $19 . The price is 12% lower than last week.
grandymaker [24]
Here is the solution for the given problem above.
First we need to get the 12% of $19. So 19 x 0.12 and we get 2.28. So in order to get the price of the DVD last week, let us add the 2.28 to 19, and we get a total of 21.28. So the final answer would be: $21.28 is the price of the DVD last week. Hope this answers the question. Thanks for posting your question.
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3 years ago
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Simplify using the multiplication rule.
goldenfox [79]

A. the first one is the answer

Step-by-step explanation:

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3 years ago
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