Given sets A, B, C, and U, find the elements in A - B'.

Mathematics

1 answer:

SpyIntel [72]2 years ago

8 0

Step-by-step explanation:

note A- b = A n B

so, ( A n B ) = ( 3, 4 )

( A n B )' = ( 0,1,2,5,6,7)

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Im confused <br><br><br> khan academy 8th grade

Anit [1.1K]

Answer:

Step-by-step explanation:

hi! so the question is asking what h is when you input -18 for x, right?

inputing in this question means to substitute, meaning that in this equation, -18 will take the place of x!

let's see what the equation looks like now
$h = 17 + \frac{-18}{6}$
easy as that!

now let's do the math :)

because of PEMDAS, remember to do the fraction (dividing) first!
$h = 17 + (-3)$

we can change that to --> h = 17 - 3

h = 14

let me know if you're still confused!

7 0

2 years ago

Pls help with these questions I can give brainliest thank you all! 9 a and b

nata0808 [166]

Answer:

A. 8 1/4 * 11 1/2 * 14=1328 1/4 ft^2

8 1/4 height times 11 1/2 width times 14 in length equals 1328 1/4 feet squared

B. 8 1/4 * 14 1/2 * 14=1674 3/4

8 1/4 height times 11 1/2 width plus 3 so 14 1/2 width times 14 equals 1674 3/4 feet squared

Step-by-step explanation:

7 0

3 years ago

Simplify the given expression below 4/3-2i

ANTONII [103]

So-called simplifying, really means, "rationalizing the denominator", which is another way of saying, "getting rid of that pesky radical in the bottom"

$\bf \cfrac{4}{3-2i}\cdot \cfrac{3+2i}{3+2i}\impliedby \textit{multiplying by the conjugate of the bottom}
\\\\\\
\cfrac{4(3+2i)}{(3-2i)(3+2i)}\implies \cfrac{4(3+2i)}{3^2-(2i)^2}\implies \cfrac{4(3+2i)}{3^2-(4i^2)}\\\\
-------------------------------\\\\
recall\qquad i^2=-1\\\\
-------------------------------\\\\
\cfrac{4(3+2i)}{3^2-(4\cdot -1)}\implies \cfrac{4(3+2i)}{9+4}\implies \cfrac{12+8i}{13}\implies \cfrac{12}{13}+\cfrac{8}{13}i$