Let the probability of an even number occurring be p and that of odd be q. From the question, p = 2q.
Now, p and q are mutually exclusive events. Hence,
p + q = 1
2q + q = 1
3q = 1
q = 1/3
p = 2q = 2/3
There are 3 odd numbers and 3 even numbers on a die. The probability of each even number is p/3 = 2/9 and the probability of each odd number is q/3 = 1/9.
The event E is the event of a 3, 2 or 1 appearing. Here, we have two odd numbers and 1 even number.
Ratios are proportional if both serve the identical tie. A method to detect if a pair of ratios remain equivalent is to rewrite them being fractions, then decrease them. If the decreased fractions are equal, the ratios are comparative.