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Mekhanik [1.2K]
3 years ago
15

ALGEBRA 1 HELP URGENT PLEASE

Mathematics
1 answer:
sladkih [1.3K]3 years ago
6 0
I hope this helps you

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Subtract 1.05 from a certain number. Multiply the difference by 0.8, add 2.84 to the product then divide the sum by 0.01 and get
attashe74 [19]
Just do the whole process backwards
700*0.01=7
7-2.84=4.16
4.16/0.8=5.2
5.2+1.05=6.25
8 0
3 years ago
Pleaseee helppppppppppppppppppp
quester [9]

To find Angle A we use cosine

cos ∅ = adjacent / hypotenuse

From the question

The adjacent is 17

The hypotenuse is 38

So we have

cos A = 17/38

A = cos-¹ 17/38

A = 63.4

<h3>A = 63° to the nearest degree</h3>

To find Angle C we use sine

sin ∅ = opposite / hypotenuse

From the question

The opposite is 17

The hypotenuse is 38

So we have

sin C = 17/38

C = sin-¹ 17/38

C = 26.57

<h3>C = 27° to the nearest degree</h3>

Hope this helps you

7 0
3 years ago
Prove that sec^4 (x)=1+2 tan^2 (x)+tan^4 (x)
IgorC [24]

Answer: sec^4(x)-tan^4(x) = 1+2 x tan^2(x)

Step-by-step explanation:

7 0
3 years ago
The end of the rain gutter has the shape of a trapezoid with the measurements shown. Find the area of this end.
sladkih [1.3K]
Area = 1/2 × (Sum of parallel sides) × height

Area = 1/2 × (6+4) × 4 = 10×2 =20in ^2

AREA = 20 in squared

HOPE THIS WILL HELP U
5 0
3 years ago
Read 2 more answers
What is the area of this<br>irregular shape?<br>.6 ft<br>square feet<br>3 ft<br>8 ft<br>16 ft<br>​
Andrej [43]

Answer:

Step-by-step explanation:

area=16×8+1/2×3×6

=128+9

=137 sq. ft.

5 0
3 years ago
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