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ArbitrLikvidat [17]
3 years ago
5

Find the value of x (help quick)

Mathematics
1 answer:
o-na [289]3 years ago
6 0

Answer:

c) 3

Step-by-step explanation:

22=2x2 +4

22-4

18=2x2

18/2

9=x2

x=3

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Alexus [3.1K]
I think it is 5 but I am not for sure
8 0
3 years ago
Read 2 more answers
Which shows the proper use of the distributive property
Karo-lina-s [1.5K]

Answer:

-2 (6x - y) = -12x + 2y

Step-by-step explanation:

By using the distributive property, you start by multiplying -2 and 6x which gets you -12x. You then multiply -2 and -y (in other words -y = -1y) so, -2* -y would get you 2 as a negative multiplied by a negative is a positive. So, adding them together would get your final answer: -2 (6x - y) = -12x + 2y

5 0
3 years ago
Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that
Maksim231197 [3]

Complete Question

The Brown's Ferry incident of 1975 focused national attention on the ever-present danger of fires breaking out in nuclear power plants. The Nuclear Regulatory Commission has estimated that with present technology there will be on average, one fire for every 10 years for a reactor. Suppose that a certain state has two reactors on line in 2020 and they behave independently of one another. Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that by 2030 at least two fires will have occurred at these reactors?

Answer:

The value is P(x_1 + x_2 \ge 2 )= 0.5940

Step-by-step explanation:

From the question we are told that

     The rate at which fire breaks out every 10 years is  \lambda  =  1

  Generally the probability distribution function for Poisson distribution is mathematically represented as

               P(x) =  \frac{\lambda^x}{ k! } * e^{-\lambda}

Here x represent the number of state which is  2 i.e x_1 \ \ and \ \ x_2

Generally  the probability that by 2030 at least two fires will have occurred at these reactors is mathematically represented as

          P(x_1 + x_2 \ge 2 ) =  1 - P(x_1 + x_2 \le 1 )

=>        P(x_1 + x_2 \ge 2 ) =  1 - [P(x_1 + x_2 = 0 ) + P( x_1 + x_2 = 1 )]

=>        P(x_1 + x_2 \ge 2 ) =  1 - [ P(x_1  = 0 ,  x_2 = 0 ) + P( x_1 = 0 , x_2 = 1 ) + P(x_1 , x_2 = 0)]

=>  P(x_1 + x_2 \ge 2 ) =  1 - P(x_1 = 0)P(x_2 = 0 ) + P( x_1 = 0 ) P( x_2 = 1 )+ P(x_1 = 1 )P(x_2 = 0)

=>    P(x_1 + x_2 \ge 2 ) =  1 - \{ [ \frac{1^0}{ 0! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]] )+ ( [ \frac{1^1}{1! } * e^{-1}] * [[ \frac{1^1}{ 1! } * e^{-1}]] ) + ( [ \frac{1^1}{ 1! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]]) \}

=>   P(x_1 + x_2 \ge 2 )= 1- [[0.3678  * 0.3679] + [0.3678  * 0.3679] + [0.3678  * 0.3679]  ]

P(x_1 + x_2 \ge 2 )= 0.5940

               

3 0
3 years ago
Can I have help help on 22,24,26,28,30 please
Dmitriy789 [7]
I'll do 22 for you. 22, 24, 26, 28, and 30, are very similar to each other.

PROPORTIONS:
Draw it out.

5/7 = either c/6, or b/5. 
I'll do c/6
5/7 = c/6
solve for c
7c=30
c=30/7
now do the same thing to the remaining side, b.
there!

4 0
3 years ago
The ratio of Rogers age to his sons is 7:3. If the sum of their ages are 60 how old is Rogers son
Nimfa-mama [501]

Answer:24

Step-by-step explanation:

Sum of their ages is 60 yr. As such

7x + 3x = 60

10x = 60

x = 60 / 10

x = 6

The rationale is 6, therefore

Father's age is 7x = 7 × 6= 42 years

Son's age is 3x = 3 × 6 = 18 years

Difference in their ages

42 - 18 = 24 years

5 0
3 years ago
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