Solution :
Transforming given equations :
![1)\ P = 600( 1 + \dfrac{12}{100})^t\\\\2)\ P = 1000( 1 + \dfrac{3}{100})^t\\\\3)\ P = 200( 1 + \dfrac{8}{100})^t\\\\4)\ P = 900( 1 - \dfrac{10}{100})^t](https://tex.z-dn.net/?f=1%29%5C%20P%20%3D%20600%28%201%20%2B%20%5Cdfrac%7B12%7D%7B100%7D%29%5Et%5C%5C%5C%5C2%29%5C%20P%20%3D%201000%28%201%20%2B%20%5Cdfrac%7B3%7D%7B100%7D%29%5Et%5C%5C%5C%5C3%29%5C%20P%20%3D%20200%28%201%20%2B%20%5Cdfrac%7B8%7D%7B100%7D%29%5Et%5C%5C%5C%5C4%29%5C%20P%20%3D%20900%28%201%20-%20%5Cdfrac%7B10%7D%7B100%7D%29%5Et)
From above equations we can see that equation 1) has largest percentage growth rate and the percent growth rate is 12% .
Hence, this is the required solution.
steps
(x) = 5x^2-3x+7
refine
x=5x^2-3x+7
Switch sides
5x^2-3x+7-x=x-x
Subtract x from both sides
5x^2-4x+7=0
Solve with the quadratic formula
Answer:
5/25, 1/5, or 20%
Step-by-step explanation:
Based on the experiment the dice lands on 2 five times, giving you the experimental probability
A is 110, B is 70, C is 110, D is 70, G is 110, E is 110, and F is 70
Answer:
29000, with the margin of error of ±5000
Step-by-step explanation:
Margin of error is the amount of error that can be caused due to variation, change of circumstances or any miscalculation.
In given case value of college student's debt can be between
24000 and 34000
Finding mid-point
(24000+34000)/2
29000
Now finding deviation of 29000 from 24000 and 34000
24000-29000= -5000
34000-29000= 5000
Hence
29000, with the margin of error of ±5000 !