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Degger [83]
3 years ago
11

Question: 23 of 60

Mathematics
1 answer:
Ronch [10]3 years ago
3 0
The correct answer is 40 which will be letter c
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Tobeg says the equation 3x + 2y= 270 and y=4/5x + 20 intersect at the point (50,60) is this true how do you know
il63 [147K]

ANSWER

Yes it is very true


<u>EXPLANATION</u>

If the two equations intersect at (50,60) then this point must satisfy the two equations.


3x+2y=270---(1)

We substitute  (50,60)  in to erquation (1)


3(50)+2(60)=270


150+120=270

270=270




y=\frac{4}{5}x+20 ---(2)


We now substitute  (50,60)  in to erquation (2) also


60=\frac{4}{5}(50)+20


60=40+20


60=60


Since the point satisfy all the two equations, it is true that they intersect at (60,50)




3 0
3 years ago
Pleas I need help now
Zina [86]
I can't see the picture it is too small
8 0
2 years ago
How many inches are in 1 mile? (5280ft = 1mi; 12in = 1ft)
7nadin3 [17]

1 mile * 5280 ft * 12 in = 63360 in

There are 63360 inches in one mile

4 0
3 years ago
Read 2 more answers
Which fact is related to 12 = 3 = 4?<br> I need help
Svetach [21]

Answer:

factors

Step-by-step explanation:

3 0
3 years ago
a square dance set requires 4 couples 8 dancers with each couple standing on one side of a square. There are 250 people at a squ
sveta [45]

Given:

1 set requires 4 couples 8 dancers.

Total number of people at a square dance = 250.

To find:

The greatest number of sets possible at the dance.

Solution:

We have,

Total people = 250

1 set = 8 people.

\text{Number of possible sets}=\dfrac{\text{Total people}}{\text{People required for 1 set}}

\text{Number of possible sets}=\dfrac{250}{8}

\text{Number of possible sets}=31.25

Number of possible sets cannot be a decimal or fraction value. So, approx. the value to the preceding integer.

\text{Number of possible sets}\approx 31

Therefore, the number of possible sets at the dance is 31.

7 0
2 years ago
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