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Ymorist [56]
4 years ago
8

Help pls I will give 20 points

Mathematics
1 answer:
dalvyx [7]4 years ago
4 0

Answer:

neon-0

oxide- -2

copper-2

tin-0

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Please help!
nevsk [136]
The correct answer is
C.
Explanation:
4 - 2(-4) =12, 4 - 2(0) =4, 4 - 2(5) =-6
4 0
3 years ago
Read 2 more answers
Find the radius r of the circle. Round your answer to the nearest tenth.
Genrish500 [490]

First off we need to use the formula S = rΘ

S - is the arc length

Θ - is theta which is the radian measure

r - is the radius

In this problem we need to find r

So, our equation would look like:

S ÷ Θ = r

Before we solve though, we need to convert the degrees to radians:

To convert from degrees to radians, multiply the degrees by π/180° radians:

60 x π/180 = 1.0472

If you input the numbers you get:

10.2 / 1.0472 = 9.740

The radius is 9.7 yards.

4 0
3 years ago
How to Break apart 3x7
stiv31 [10]
Well brake 7 into 5 and 2 and then  just multiply it by 3 so it would be 5 x3=15 and 2x3=6 then u add 15+6 it would be the sum, of 21 so 3x7=21
5 0
3 years ago
Given f(x) and g(x) = f(x) + k, use the graph to determine the value of k.<br> g(x)<br> f(x)
vlada-n [284]

Answer:

k = 4

Step-by-step explanation:

First, find the equations of each function.

f(x) = x/3 - 3

g(x) = x/3 + 1

Then plug these values for g(x) = f(x) + k.

x/3 + 1 = x/3 - 3 + k          subtract x/3 on both sides

1 = -3 + k                          add -3 on both sides

k = 4                                we're done!

and this makes sense because g(x) is just a translation of f(x) 4 units up.

5 0
2 years ago
the figure below is a square . Find the length of side x in simplest radical form with a rational denominator.
wel

Answer:

\sqrt{14}

Step-by-step explanation:

In any square with side length s, the diagonal of the square is equal to s\sqrt{2}. Since the side length of this square is \sqrt{7}, the diagonal is equal to \sqrt{7}\cdot \sqrt{2}=\boxed{\sqrt{14}}.

Alternatively, you can form two 45-45-90 triangles with the diagonal of the square. The diagonal acts as the hypotenuse for the both these triangles, and the legs of both triangles are equal to the side length of the square. To find the length of the diagonal, use the Pythagorean Theorem, which states a^2+b^2=c^2, where c is the hypotenuse of the triangle, and a and b are the two legs of the triangle.

In this question, both legs are equal to \sqrt{7}, and we're solving for the diagonal, which is the hypotenuse in this case:

\sqrt{7}^2+\sqrt{7}^2=c^2,\\c^2=14,\\c=\boxed{\sqrt{14}}

4 0
3 years ago
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