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Travka [436]
3 years ago
10

I don't know how to do this.​

Mathematics
1 answer:
mel-nik [20]3 years ago
8 0

Answer:

I need help on this to it's confusing

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How do you solve 5(3x+7) =3 (5x+7) ?
Naya [18.7K]
5(3x+7)=3(5x+7)

15x+35=15x+21

cancel out the 15x. If you bring over one of the 15x it's going to naturally cancel each other out.

35=21

35 does not equal 21

it would be the equal sign with the slash coming through it
4 0
3 years ago
Hamburgers cost $2 and hotdogs cost $2. The total cost of buying b hamburgers and d hotdoge can be expressed by C=3b+2d. how can
sveticcg [70]
C= 3b + 2d
Subtract 3b first.

C-3b = 2d
Divide by 2.

C-3b/2 = d

OR

C-3b
-------- = d Your final answer!
2
3 0
3 years ago
If one angle of a set of supplementary angles measures 77°, then the other angle measures _____.
VikaD [51]

If two angles are supplementary, then

the sum of their measures is 180°.

So if the measure of an angle is 77°,

the measure of its supplement is 103°.

We can find the measure of its supplement by taking 180 minus the measure of the original angle which in this case is 180 - 77 or 103°.

4 0
3 years ago
Read 2 more answers
The table below shows some inputs and outputs of the invertible function f with domain all real numbers. NEED HELP NOW!!!!!
Serggg [28]

Answer:

( 1 ) f^{-1}(f(576)) = 576,

( 2 ) f^{-1}(-7)+f(-7) = 13

Step-by-step explanation:

Taking the function and it's inverse, it should be the following property -

f^{-1}(f(x))= x - this therefore makes the functionality " f^{-1}(f(576))= x " equivalent to 576 itself.

For this second part here let's consider the portion " f(-7) " firstly. As you can see from the table, - 7 should represent the x - value, hence f(-7) = 7. Now for this second bit here, we have to take the inverse - making the what should have been the x - value, now the f( x ) value. Therefore, f^{-1}(-7) = 6.

This would make f^{-1}(-7)+f(-7) = 7+6 = 13.

4 0
4 years ago
(2a-3)(b-a)-3a(3a+b)
ozzi

Answer: -ab - 11a^2 - 3b + 3a

Step-by-step explanation:

i think this is what you're wanting? if not just comment what you need and i'll retry it!

3 0
3 years ago
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