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3 years ago

14

Can someone help me

1 answer:

Colt1911 [192]3 years ago

3 0

The answer is B. (-1,3) hope this helped

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Joshua works in a department store selling clothing. He makes a guaranteed salary of

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Answer:

contesta la pregunta tú sólo déjame en paz

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3 years ago

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Rhonda is painting four pictures on paper. She has 1/8 of a gallon of paint to paint all the pictures. How much paint will she u

Doss [256]

Answer:

1/32

Step-by-step explanation:

To determine the amount of paint she would use for a picture, divide the total gallon of paint by the number of pictures

Paint she would use for one painting = total gallons of paint / number of pictures

1/8 ÷ 4

= 1/8 x 1/4

= 1/32

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3 years ago

On a test, Leo is asked to completely factor the polynomial 3x3 – 3x + 5x2 – 5. He uses double grouping to get (x2 – 1)(3x + 5).

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Answer:

Leo does not factored the polynomial completely.

3x^3-3x+5x^2-5=(x+1)(x-1)(3x+5)

Step-by-step explanation:

Given: On a test, Leo is asked to completely factor the polynomial

3x^3-3x+5x^2-5.

also, he uses double grouping to get (x^2- 1)(3x+5)

We have to explain whether he factored the polynomial completely or not.

Consider the given polynomial 3x^3-3x+5x^2-5.

after double grouping he get (x^2- 1)(3x+5)

Also, we can simplify further ,

Using algebraic identity a^2-b^2=(a+b)(a-b)

We get,

(x^2- 1)=(x+1)(x-1)

We get, (x^2- 1)(3x+5)=(x+1)(x-1)(3x+5)

Thus, 3x^3-3x+5x^2-5=(x+1)(x-1)(3x+5)

Thus, He does not factored the polynomial completely.

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Help with this math thing please!

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Answer:

i cant see

Step-by-step explanation:

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3 years ago

Suppose that P(n) is a propositional function. Determine for which nonnegative integers n the statement P(n) must be true if a)

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Solution :

a). $P(0)$ is true

Then , $P(0+2)=P(2)$ is true.

$P(2+2)=P(4)$ is true

$P(4+2)=P(6)$ is true.

Therefore, we see that $P(n)$ is true for all the even integers : $\{0, 2,4,6,...\}$

b). $P(0)$ is true

Then , $P(0+3)=P(3)$ is true.

$P(3+3)=P(6)$ is true

$P(6+3)=P(9)$ is true.

Therefore, we see that $P(n)$ is true for all the multiples of 3 : $\{0, 3,6,9,12,...\}$

c). $P(0)$ and $P(1)$ is true, then $P(0+2)=P(2)$ is true

$P(1)$ and $P(2)$ is true, then $P(1+2)=P(3)$ is true.

$P(2)$ and $P(3)$ is true, then $P(2+2)=P(4)$ is true.

So, we observe that $P(n)$ is true for all the non- negative integers : $\{0, 1,2,3,4,5,6,...\}$ .

d). $P(0)$ is true,

So, $P(0+2)$ and $P(0+3)$ is true or $P(2)$ and $P(3)$ is true.

Now, $P(2)$ is true.

Again, $P(2+2)$ and $P(2+3)$ is true or $P(4)$ and $P(5)$ is true.

Now, $P(3)$ is true.

Again, $P(3+2)$ and $P(3+3)$ is true or $P(5)$ and $P(6)$ is true.

Thus,

$P(n)$ is true for all the non- negative integers except 1 : $\{0, 2,3,4,5,6,...\}$ .

3 0

3 years ago