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Yakvenalex [24]

3 years ago

7

In order to prepare for the test, Janet purchases an activity tracker to record her steps. Her goal is to walk 10,000 steps each

day. She measures her average step length to be 30 inches. When Janet runs, her average step length increases to 36 inches. How many steps would she have to take to run 1 mile (5,280 feet)? Round to the nearest step.

2 answers:

vampirchik [111]3 years ago

4 0

Janet would take 1,760 steps

Digiron [165]3 years ago

4 0

Answer:

it would be 1,760

Step-by-step explanation:

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Jordan takes out $50 from his bank account each week. He started with $725.

Margarita [4]

D because -50x is the amount you’re subtracting from the total

5 0

3 years ago

Help me for 20 points.

Rom4ik [11]

1. Find angle Y. Since the interior angles of a triangle must add up to 180 deg., we have 180 - (98+24) = 58 deg.

Apply the Law of Sines to determine the lengths of sides r and t:

r 7.9 t
--------- = --------- = ---------
sin 98 sin 58 sin 24

Then r = (7.9 sin 98)/ (sin 58) = 9.22. This matches r in the 2nd choice. Determine t using the same method: t = 7.9sin 24 / sin 58.

Does your t value match that in the 2nd possible answer?

3 0

4 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

4 years ago

In triangle ABC, the length of side AB is 17 inches and the length of side BC is 23 inches. Which of the following could be the

Sliva [168]

17^2 = 289
23^2 = 529

529 + 289 = 818

√818 = 28.6 inches

4 0

4 years ago

Given the parametric equations x = 7cos θ and y = 5sin θ, which of the following represents the curve and its orientation?

nikitadnepr [17]

We have the following parameters

$\begin{gathered} x=7cos\theta \\ y=5sin\theta \end{gathered}$

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$x^2+y^2=r^2$

Let's use the following tigonometric identity,

$sin^2\theta+cos^2\theta=1$

solving for cos and sin in the equations we are given,

$cos\theta=\frac{x}{7},sin\theta=\frac{y}{5}$

replace,

$(\frac{y}{5})^2+(\frac{x}{7})^2=1$

Since we have two different numbers in the denominator, this is not a circle equation but an elipse, of the form,

$\frac{y^2}{a^2}+\frac{x^2}{b^2}=1$

where,

a is the vertex and,

b is the covertex

thus, in the x axis, the vertex is 7 and the y-axis the covertex is 5

Now, let's determine the direction by replacing

when Θ = 0 , then x = 7*cos0 = 7*1 = 7 , and y = 5*sin0 = 5*0 = 0

when Θ = 90° or π/2 , then x = 7*cos90° = 7*0 = 0 , and y = 5sin90° = 5*1 = 5

If we draw this, we can see that the direction is counterclockwise as in the bottom right image.

6 0

1 year ago