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2 years ago

Which expressions are equivalent to

Mathematics

2 answers:

Novay_Z [31]2 years ago

6 0

I can’t see the part after “Choose 3 answers:”

Wish I could help you :)

Naya [18.7K]2 years ago

5 0

Answer: first: 16a+20 second: 12a+20+4a third: 2(8a+10)

Step-by-step explanation:

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Simplify the expression –3(x 3)2 – 3 3x. what is the simplified expression in standard form?

777dan777 [17]

$-3(x^{2} +5x+10)$ is the standard form of the given expression

The given expression is:

$=-3(x+3)^{2} -3+3x\\\\=-3*(x^{2} +2*3*x+3^{2} )-3+3x\\\\=-3x^{2} -3*6x-3*9-3+3x\\\\=-3x^{2} -18x-27-3+3x\\\\=-3x^{2} -15x-30\\\\=-3(x^{2} +5x+10)$

This is the standard form of the given expression.

Learn more about Simplifying expression here brainly.com/question/723406

#SPJ4

7 0

2 years ago

Finding values or k(x) = x - 2 h(x) = x2 +1 (h + k)(2) =

Serjik [45]

Answer:

Step-by-step explanation:

$(h+k)(x)=h(x)+k(x)\\\\\bold{METHOD\ 1:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(k+h)(2)=h(2)+k(2)\\\\\text{Calculate}\ h(2)\ \text{and}\ k(2).\\\text{Put}\ x=2\ \text{to the equations of the functions}\\\\h(2)=2^2+1=4+1=5\\k(2)=2-2=0\\\\\text\\\\\text{Substitute:}\\\\(h+k)(2)=5+0=5$

$\bold{METHOD\ 2:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(h+k)(x)=h(x)+k(x)=(x^2+1)+(x-2)=x^2+x-1\\\\(h+k)(2)-\text{put}\ x=2\\\\(h+k)(2)=2^2+2-1=4+2-1=6-1=5$

5 0

2 years ago

jenna's rectangular garden borders a wall. she buys 80 ft of fencing. what are the dimensions of the garden that will maximize i

FrozenT [24]

Answer:

The dimensions are x =20 and y=20 of the garden that will maximize its area is 400

Step-by-step explanation:

Step 1:-

let 'x' be the length and the 'y' be the width of the rectangle

given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is 2(x +y) = 80

x + y =40

y = 40 -x

now the area of the rectangle A = length X width

A = x y

substitute 'y' value in above A = x (40 - x)

A = 40 x - x^2 .....(1)

Step :2

now differentiating equation (1) with respective to 'x'

$\frac{dA}{dx} = 40 -2x$ ........(2)

Find the dimensions

$\frac{dA}{dx} = 0$

40 - 2x =0

40 = 2x

x = 20

and y = 40 - x = 40 -20 =20

The dimensions are x =20 and y=20

length = 20 and breadth = 20

Step 3:-

we have to find maximum area

Again differentiating equation (2) with respective to 'x' we get

$\frac{d^2A}{dx^2} = -2$

Now the maximum area A = x y at x =20 and y=20

A = 20 X 20 = 400

Conclusion:-

The dimensions are x =20 and y=20 of the garden that will maximize its area is 400

verification:-

The perimeter = 2(x +y) =80

2(20 +20) =80

2(40) =80

80 =80

8 0

3 years ago

Please help :( Im desperate

ki77a [65]

Answer:

(2,4)

Step-by-step explanation:

When graphed the lines intersect at point (2,4) which is the solution.

8 0

2 years ago

Say that you put the set of tiles shown below into a bag and conduct a series of trials in which you draw one tile randomly from

Karolina [17]

Answer:

letter. c

Step-by-step explanation:

8 0

3 years ago