To solve the problem it is necessary to take into account the concepts of the kinetic equations for the description of the torque at the rate of force and distance.
By definition the torque is given by,
where,
For the problem in question the mass of the trophy is 1.64Kg and the distance of the tropeo to the board (the shoulder) is 0.655m
PART A) For part A, the torque with the given mass and the stipulated torque in the horizontal plane must be calculated as well,
For Newton's second law
PART B) For part B there is an angle of 26 degrees with respect to the horizontal, therefore to know the net torque it is necessary to know the horizontal component to the formed angle, that is,
Answer:
14.2
Explanation:
find horizontal force of the weight = 2.5kg x 9.8 Sin30 = 12.3 N
to prevent the sliding she needs to pull horizontally
Fh = 12.3 /Cos 30 =14.2N
Answer:It depends on the initial velocity of the projectile and the angle of projection. The maximum height of the projectile is when the projectile reaches zero vertical velocity. ... The horizontal displacement of the projectile is called the range of the projectile and depends on the initial velocity of the object
Answer:
0.0118125 (kg)
Explanation:
mass = density x volume
First, find the volume of the cube as you're already given the density. You're also given the length of the cube, 1.5 cm. You need to convert this to m since the density's unit is kg/m^2
1.5cm x (1m/100cm) = 0.015m
Since Volume = (length)^3,
Volume of the cube = (0.015)^3
Volume of the cube = 3.375*10^-6
So mass of the cube = (3500)(3.375*10^-6) = 0.0118125 (kg)
Answer:
The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases
