Answer:
Explanation:
capacitance of sphere 2 will be 4.5 times sphere 1
a ) when spheres are in contact they will have same potential finally . So
V_1 / V_2 = 1
b )
Charge will be distributed in the ratio of their capacity
charge on sphere1 = q x 1 / ( 1 + 4.5 )
= q / 5.5
fraction = 1 / 5.5
c ) charge on sphere 2
= q x 4.5 / 5.5
fraction = 4.5 / 5.5
d ) surface charge density of sphere 1
= q /( 5.5 x A ) where A is surface area
surface charge density of sphere 2
= q x 4.5 /( 5.5 x 4.5² A ) where A is surface area
= q /( 5.5 x 4.5 A )
q_1/q_2 = 4.5
When in orbit, a satellite such as the space shuttle s <span>in non-accelerated motion. </span>
First we needed to find the area of floor ( wish the dimensions were clarified to be the floor dimensions) then we take the area and divide by 32 square feet
Answer:
Option B
Explanation:
Displacement = Area under the velocity-time graph
So to find the displacement of a particle from 7 to 8 seconds we take the triangle and calculate its area.

So the displacement is 1.5 meters
I have an uploaded image so you can understand it better hope it helps