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vfiekz [6]
3 years ago
14

A car is moving with the velocity of 90km/h. If the car come to rest after 10 seconds. Calculate the final velocity and distance

covered by the car within that time.
plz wirte the full formula ​
Physics
1 answer:
djyliett [7]3 years ago
6 0

Answer:

you can learn from here

https://www.toppr.com/ask/en-bd/question/a-car-is-moving-with-a-velocity-of-10-ms-the-driver-sees-a-wall/

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A 25 kh inductor carries a current of 60 ma. how much energy is stored in this system
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A spring with spring constant of 34 N/m is stretched 0.12 m from its equilibrium position. How much work must be done to stretch
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Answer:0.253Joules

Explanation:

First, we will calculate the force required to stretch the string. According to Hooke's law, the force applied to an elastic material or string is directly proportional to its extension.

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e is the extension = 0.12m

F = 34× 0.12 = 4.08N

To get work done,

Work is said to be done if the force applied to an object cause the body to move a distance from its initial position.

Work done = Force × Distance

Since F = 4.08m, distance = 0.062m

Work done = 4.08 × 0.062

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Therefore, work done to stretch the string to an additional 0.062 m distance is 0.253Joules

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Determine the rate at which the electric field changes between the round plates of a capacitor, 8.0 cm in diameter, if the plate
Daniel [21]

Solution:

The relation between the potential difference and the electric field between the plates of the parallel plate capacitor is given by :

$E=\frac{V}{D}$

Differentiating on both the sides with respect to time, we get

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Therefore, the rate of the electric field changes between the plates of the parallel plate capacitor is given by :

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      $=7.85 \times 10^4$  V/m-s

8 0
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