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kipiarov [429]
3 years ago
9

Franks credit card has no annual fee, 23.99% interest rate. Switch to new card 16.99% rate. $35 annual fee. How much average bal

ance would frank have to make switching cards worth it?
Mathematics
1 answer:
Luda [366]3 years ago
7 0

Answer:

<em>The minimum average balance that makes the switching worth it is $500</em>

Step-by-step explanation:

<u>Equations</u>

We know Frank's credit card has no annual fees and charges an interest rate of 23.99% of his average balance B. He wants to switch to a new card with $35 annual fees but less interest rate of 16.99%.

The total annual payment Frank actually has to pay is given only by the interest of his annual average balance. That is

P_1=23.99\%\cdot B=0.2399\cdot B

With the new card, he'll have to pay a fixed fee of $35 plus the annual interest:

P_2=35+16.99\%\cdot B=35+0.1699\cdot B

To make switching cards worth it, both payments will need to be (at least) equal:

0.2399\cdot B=35+0.1699\cdot B

Rearranging

0.2399\cdot B-0.1699\cdot B=35

0.07B=35

Solving

B=35/0.07=500

B=\$500

The minimum average balance that makes the switching worth it is $500. If his balance is more than $500, he'll save by using the new card.

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Solve for x.<br><br> A. 37<br> B. 27<br> C. 30<br> D. 31
dexar [7]

Answer:

B

Step-by-step explanation:

The formula for finding the relationship between a secant and a tangent is

tangent length ^2 = external segment secant/full length of secant

In this case

60^2 = 48*(x + 48)                   Expand

3600 = 48*(x + 48)                  Remove the brackets/

3600 = 48x + 48^2                 Expand

3600 = 48x + 2304                Subtract 2304 from both sides

3600 - 2304 = 48x              

1296 = 48x                              Divide both sides by 48

1296 / 48 = x        

x = 27

8 0
2 years ago
Since the subject of Shakespeare's poem is disloyalty and ingratitude – things that are not jolly – the lines "Then heigh-ho, th
sergejj [24]
This is a guess, but I think its A. I could be wrong though.
4 0
3 years ago
23<br> (12v + 5)<br> 95<br> Need help!
IgorC [24]

doo

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Step-by-step explanation:

7 0
3 years ago
Me. Ellis is a teacher who tutors after school. Of the students he tutors, 30% need help in computer science and 70% need assist
Anna11 [10]

Answer: There are 82.5% after school students who are enrolled in his classes.

Step-by-step explanation:

Let the total number of students be 100

Percentage of students who need help in computer science = 30%

So, number of students who need help in computer science = 30

Percentage of students who need help in maths = 70%

So, number of students who need assistance in maths  = 70

Of the students who need help,

40% are enrolled in Mr. Ellis's class during the school day,

So, it means 60% are enrolled in his class after the school day.

Number of students who are enrolled in his class after the school day = 60

Number of students who need help in Maths is given by

\frac{70}{100}\times 60=42

Of the students that need help in maths, percent of students are enrolled in his class during the day = 25%

So, number of students who need help in maths and enrolled in his class after school hours

\frac{75}{100}\times 42=31.5

Number of students who need help in computer science and enrolled in his class after school hours

\frac{30}{100}\times 60=18

Therefore, there are 31.5+18=49.5 students who joined his class after school hours,

Percentage of the after students who are enrolled in Mr. Ellis's classes is given by

\frac{49.5}{60}\times 100=82.5\%

Hence, there are 82.5% after school students who are enrolled in his classes.


6 0
3 years ago
Hannah got a perfect score on 3 more spelling quizzes this quarter than last quarter . If she doubles the number of perfect quiz
algol13
First, underline the key numbers

n=Perfect Quizzes last quarter

x=School record

n+3

3•2=x

Now we solve that

3•2=6

Now we know, x=6

If the record (6) is 3 times the number of spelling quizzes Hannah scored perfectly last quarter (n), then we know we have to divide the record (6) by 3 to know how many perfect quizzes were from last quarter.

6/3=2 so, n=2

The number of perfectly scored quizzes from last quarter is 2.

7 0
3 years ago
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