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AnnZ [28]
3 years ago
9

A jewelry manufacturer makes pendants with 1 and 1/2 ounces of silver in each. It has

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
8 0
Do repeated addition to 1 and 1/2 to get the answer
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Find the midpoint of the line segment defined by the points: (5, 4) and (−2, 1) (2.5, 1.5) (3.5, 2.5) (1.5, 2.5) (3.5, 1.5)
Setler79 [48]

Answer:

\boxed {\boxed {\sf (1.5 , 2.5)}}

Step-by-step explanation:

The midpoint is the point that bisects a line segment or divides it into 2 equal halves. The formula is essentially finding the average of the 2 points.

(\frac {x_1+x_2}{2}, \frac {y_1+ y_2}{2})

In this formula, (x₁, y₁) and (x₂, y₂) are the 2 endpoints of the line segment. For this problem, these are (5,4 ) and (-2, 1).

  • x₁= 5
  • y₁= 4
  • x₂= -2
  • y₂= 1

Substitute these values into the formula.

( \frac {5+ -2}{2}, \frac {4+1}{2})

Solve the numerators.

  • 5+ -2 = 5-2 = 3
  • 4+1 = 5

( \frac {3}{2}, \frac{5}{2})

Convert the fractions to decimals.

(1.5, 2.5)

The midpoint of the line segment is (1.5 , 2.5)

3 0
3 years ago
Let F(x,y)=1+sqrt(4-y^2). . (a) Evaluate F(3,1). (b) Find and sketch the domain of F. (c) Find the range of F
charle [14.2K]
The goal of this function is to get  a positive value under the square root sign so that the value would not be invalid. Evaluating F(3,1), the value is 1 + <span>sqrt(4-1^2) or equal to 1 + sqrt of 3.</span> In this case, the domain would be x equal to any numbers and the range equal to numbers from -2 ≤ y ≤ 2. 
6 0
3 years ago
Read 2 more answers
Plz help me plz f(87) = -590.6 and f(132) = -901.1
quester [9]

Answer:

  ididk

Step-by-step explanation:

  ddkkdk

4 0
3 years ago
Can anyone help me???
natita [175]

Answer:

principal (p)=$1300

Interest (I) =$28.67

Time( T) = 1 year

R=?

we have,

R = I*100/T*R

5 0
2 years ago
Dan buys a car for £2100.
SVETLANKA909090 [29]

Answer:

£1837.5

Step-by-step explanation:

Given data

Cost of car P=  £2100.

Rate r= 2.2%

Time t= 6 years

Now we want to find the  worth after 6 years, let us apply the compound interest expression but this time for depreciation

A= P(1-r)^t

Substitute

A= 2100(1-0.022)^6

A= 2100*(0.978)^6

A= 2100*0.875

A= £1837.5

Hence the amount of the car after 6 years is £1837.5

8 0
3 years ago
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