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padilas [110]
4 years ago
9

Simplify the polynomial: 2a–3b+c–(4a+7b+c+3) 15 points

Mathematics
2 answers:
pogonyaev4 years ago
7 0

Answer:

-2a-10b-3

Step-by-step explanation:

Zigmanuir [339]4 years ago
7 0

Welcome to Brainly.

To start out the problem, remove the parentheses.

2a - 3b + c - 4a - 7b - c - 3\\ (2a -4a) + (-3b - 7b) + (c - c) - 3\\\boxed{-2a - 10b - 3]}

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Speed=distance traveled/time of the travel=78/2=39 mph
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3 years ago
Create and answer your
shutvik [7]

Step-by-step explanation:

\frac{20}{48}  \times  \frac{80}{44}

Divide the fraction with 4

\frac{20÷4}{48÷4} \times \frac{80÷4}{44÷4} = \frac{5}{12}  \times  \frac{20}{11}

Reduce the number with factor 4

\frac{5}{12÷4} \times \frac{20÷4}{11} = \frac{5}{3}   \times  \frac{5}{11}

Multiply the fractions

\frac{5 \times 5}{3 \times 11}  =  \frac{25}{33}

\boxed{\green{=  \frac{25}{33}  = 0.75}}

7 0
2 years ago
Read 2 more answers
In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
diamong [38]

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

4 0
3 years ago
Which statement is a correct interpretation of the vertical line test?
bulgar [2K]

Answer:

A and D

because those are the correct ones :)

4 0
3 years ago
The decline of salmon fisheries along the Columbia River in Oregon has caused great concern among Predaceous Fishes on Out-Migra
sergey [27]

Answer:

The correct answer is f) none

Step-by-step explanation:

7 0
3 years ago
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