It looks like your equations are
7M - 2t = -30
5t - 12M = 115
<u>Solving by substitution</u>
Solve either equation for one variable. For example,
7M - 2t = -30 ⇒ t = (7M + 30)/2
Substitute this into the other equation and solve for M.
5 × (7M + 30)/2 - 12M = 115
5 (7M + 30) - 24M = 230
35M + 150 - 24M = 230
11M = 80
M = 80/11
Now solve for t.
t = (7 × (80/11) + 30)/2
t = (560/11 + 30)/2
t = (890/11)/2
t = 445/11
<u>Solving by elimination</u>
Multiply both equations by an appropriate factor to make the coefficients of one of the variables sum to zero. For example,
7M - 2t = -30 ⇒ -10t + 35M = -150 … (multiply by 5)
5t - 12M = 115 ⇒ 10t - 24M = 230 … (multiply by 2)
Now combining the equations eliminates the t terms, and
(-10t + 35M) + (10t - 24M) = -150 + 230
11M = 80
M = 80/11
It follows that
7 × (80/11) - 2t = -30
560/11 - 2t = -30
2t = 890/11
t = 445/11
Answer:
Step-by-step explanation:
Given
Required
Determine the solution
Since b is a perfect square, the equation can be expressed as:
Apply difference of two squares:
Split:
Remove brackets:
Make a the subject in both equations
The solution can be represented as:
1 1/2? I pretty sure this is the answer.
Ok i tried and ig youre looking for what a and b equal for both systems..... it'll be 1) a=-2b+15 b=7.5-(1/2)a <-- fraction........2) a=-6+b b=6-a
The coordinates of the vertices of the parallelogram, given that s is a units from the origin, Z is b units from the origin, and then length of the base is c units could be the following:
W(b+c, 0), Z(b, 0), S(0, a), T(c,a)
