If the triangle were right-angled then the other 2 sides would be of length 30 / sqrt2 = 21.213 inches.
But it is acute angled so they will be a bit longer than this
they could be say 21.215 inches
So the required perimeter = 30 + 2*21.215 = 72.43 inches to nearest hundredth
Answer with Step-by-step explanation:
Let a and b are two integers.
We have to show that
if 3\a+b then 3\a-b is false.
In order to prove that given statement is false we prove this with the help of example
Suppose we have two integers a=2 and b=4
if 3\2+4
3\6=2
2-4=-2
But 3 does not divide -2.
Therefore, the given statement is false.
Hence, proved.
Answer:
x^3 +8x^2 +13
Step-by-step explanation:
(6x^2 - 3 + 5x^3) - (4x^3 - 2x^2 - 16)
Distribute the minus sign
6x^2 - 3 + 5x^3 -4x^3 + 2x^2 + 16
Combine like terms
x^3 +8x^2 +13
Answer:
The correct option is;
45°
Step-by-step explanation:
By angle sum theorem, we have that the sum of angles in a triangle = 180°
Therefore, we have;
When the interior angles of the triangle are constructed to be 60° and 75°, we have by the angle sum theorem;
The third angle + 60° + 75° = 180°
Which gives;
The third angle = 180°- 60° - 75° = 180°- 135° = 45°
The measurement of the third angle by the angle sum theorem will be 45°
The correct option is ∠third angle = 45°.
