Answer:
Length= 19cm
Width= 9cm
Step-by-step explanation:
let the length of the rectangle be L cm and its width be W cm.
Perimeter of rectangle= 56cm
2L +2W= 56
L +W= 56 ÷2
L +W= 28
L= 28 -W -----(1)
Area of rectangle= length ×width
LW= 171 -----(2)
Susbt. (1) into (2):
W(28 -W)= 171
28W -W²= 171 <em>(</em><em>expand</em><em>)</em>
W² -28W +171= 0 <em>(</em><em>bring</em><em> </em><em>everything</em><em> </em><em>to</em><em> </em><em>one</em><em> </em><em>side</em><em>)</em>
(W -19)(W-9)= 0 <em>(</em><em>factorise</em><em>)</em>
W-19=0 or W-9=0
W= 19 or W= 9
Subst into (1):
L=28 -19 or L= 28 -9
L=9 or L= 19
Since we usually take the longer side of the rectangle to be its length, L= 19 and hence W=9.
Therefore its length is 19cm and its width is 9cm.
The answer is D i think because the line has an asymptote of x = 2 and it is the only option with + 2 in the equation
The answer would be A. c^2 – b^2
If you need more help just ask :)
