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shutvik [7]
3 years ago
15

The perimeter of a rectangle below is 60 units. Find the length of side PQ

Mathematics
2 answers:
mixas84 [53]3 years ago
5 0
The answer is 17 units
erica [24]3 years ago
4 0

Answer:

17 units

Step-by-step explanation:

2{(2x + 3) + (3x + 2)} = 60

5x + 5= 60/2

5x + 5 = 30

5x = 30 - 5

5x = 25

x = 25/ 5

x = 5 units

PQ = 3x + 2 = 3*5+ 2 = 15 + 2 = 17 units

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If the point on the graph is below the origin, x coordinates must be negative.
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true

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8 0
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A custodian plans to repaint some classrooms. He has 5 = gallons of paint. All of
dlinn [17]

Answer: 2 bookcases.

Step-by-step explanation:

Let be "x" the number of bookcases that the custodian will be able to repaint completly with 5 gallons of paint.

According to the data given, the custodian needs 2 gallons of paint to repaint one bookcase. Since all the bookcases are equal, you can set up the following proportion:

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Now you must solve for "x" in order to find its value:

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5 0
3 years ago
Please help me to solve this . Thank you so much .
worty [1.4K]

Answer:

a) N

b) L

c) area I

d) area II

e) area VI

Step-by-step explanation:

a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.

b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.

c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.

d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.

e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.

5 0
3 years ago
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