Triangle QST is similar to triangle PQR
We are given that measure of angle SRP is 90°
Q is the point of the hypotenuse SP
Segment QR is perpendicular to PS and T is a point outside the triangle on the left of s
We need to find which triangle is similar to triangle PQR
So,
Using Angle - Angle - Angle Criterion We can say that
m∠PQR = m∠SQR (AAA similarity)
m∠SQR=m∠SQT (AAA similarity)
Where m∠Q =90° in ΔQST and PQR
Therefore ΔQST is similar to ΔPQR
Learn more about similarity of triangles here
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Answer:
D and E
Step-by-step explanation:
Perimeter = 4s
4(x + 8)
4x + 32
Answer:
<h2>b) 4,5,15</h2><h2 />
Step-by-step explanation:
In a triangle of sides‘s length a , b and c
in order to be able to form (construct) this triangle we must have :
c - a < b < c + a
in fact this work with cases a) ,c) and d)
but not b)
because 15 - 4 is not < to 5
in other words 15 - 4 > 5
Answer:
40.5 inch²
Step-by-step explanation:
(((6×1.5)×4)+((1.5×1.5)×2) = 40.5