240,000 rounded to the nearest hundred thousand?

Question 12 information reference tables look at each expression. is it a factor of 8x4 + 2x2 – 45 when this expression is fully

vichka [17]

8x^4 + 2x^2 - 45 = (2x^2 + 5)(4x^2 - 9) = (2x^2 + 5)(2x + 3)(2x - 3)

(a) 2x^2 + 3....no
(b) 2x^2 + 5...yes
(c) 2x - 3....yes
(d) 4x^2 - 9)...no...not when it is fully factored

3 0

3 years ago

What is -4x-10x simplified

Arte-miy333 [17]

Answer:

-14 x

Step-by-step explanation:

Simplify the following:

-4 x - 10 x

-4 x - 10 x = -14 x:

Answer: -14 x

8 0

3 years ago

Read 2 more answers

What is the equation for a Vertical Shift 5 units up?

lys-0071 [83]

F(x) = x2 + 5

This function comes from the basic function f(x) = x2 with the constant 5 added to the outside. This gives the basic function a vertical shift UP 5 units.

7 0

3 years ago

5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim

Ne4ueva [31]

Answer:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

$S_p=2.940$

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

$df=60+72-2=130$

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

$n_1 =60$ represent the sample size for people who used a self service

$n_2 =72$ represent the sample size for people who used a cashier

$\bar X_1 =5.2$ represent the sample mean for people who used a self service

$\bar X_2 =6.1$ represent the sample mean people who used a cashier

$s_1=3.1$ represent the sample standard deviation for people who used a self service

$s_2=2.8$ represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

And t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

System of hypothesis

Null hypothesis: $\mu_1 \geq \mu_2$

Alternative hypothesis: $\mu_1 < \mu_2$

This system is equivalent to:

Null hypothesis: $\mu_1 - \mu_2 \geq 0$

Alternative hypothesis: $\mu_1 -\mu_2 < 0$

We can find the pooled variance:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

And the deviation would be just the square root of the variance:

$S_p=2.940$

The statistic is given by:

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

The degrees of freedom are given by:

$df=60+72-2=130$

And now we can calculate the p value with:

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0

3 years ago

If A is a prime factor of 36, and B is a prime factor of 15, what is the greatest possible difference between A and B?

Lelechka [254]

Answer:

3

Step-by-step explanation:

Prime factorization

36 = 3 * 3 *2 * 2

15 = 3 * 5 The biggest difference is 5 -2 = 3

4 0

2 years ago