Question

Simplify. Simplify. Simplify​

Answer 1

Answer:

Step-by-step explanation:

Lots of factoring here.  Let's rewrite everything in its simplest, factored form:

$\frac{\frac{(x-1)(x+3)}{(x-4)} }{\frac{(2x-1)(x+3)}{(x+4)(x-4)} }$

The term (x - 4) cancels out completely, leaving us with

$\frac{(x-1)(x+3)}{\frac{(2x-1)(x+3)}{(x+4)} }$

Let's get rid of that (x + 4) by multiplying both top and bottom by (x + 4) to get

$\frac{(x-1)(x+3)(x+4)}{(2x-1)(x+3)}$

It's obvious now that the (x + 3) term cancels out, leaving us with

$\frac{(x-1)(x+4)}{(2x-1)}$

Now all that's left to do is to FOIL out the numerator:

$\frac{x^2+3x-4}{2x-1}$

The first choice is the one you want