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kvasek [131]
3 years ago
15

write the equation of the line in slope intercept form with the given information: through the points (-1,-9) and (2,6) how woul

d you do this?
Mathematics
1 answer:
Anit [1.1K]3 years ago
8 0
Slope intercept form isy=mx+b
m=slope
b=y intercept
ok so to find the slope when given 2 points you do
slope=(y1-y2)/(x1-x2)

(x,y)
(-1,-9)
(2,6)
x1=-1
y1=-9
x2=2
y2=6
subsitute
slope=(-9-6)/(-1-2)
slope=(-13)/(-3)
slope=13/3


y=13/3x+b
subsitute a given point to find b
(2,6)
x=2
y=6
6=13/3(2)+b
6=26/3+b
subtract 26/3 from both sides
6-26/3=b
6=18/3
18/3-26/3=8/3
8/3=b

the equation si
y=(13/3)x+8/3

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Rewrite 9 over 6 as a equivalent fraction and percent
vovangra [49]

Answer:3/2 and 150%

Step-by-step explanation:

9/6 divided by 3 on both top and bottom and get 3/2

9÷ 6= 1.5 so convert it into a percent! (move the decimal 2 places to the Right) 150%

5 0
3 years ago
How do I show my work if these are parallel or not?
JulijaS [17]

You can determine if things are parallel if the lines will eventually meet or not. M and N are one line while P and Q are also a line. Therefore, we can say P is one line while M is also one line. The answer would be is that they are parallel, the two lines will not crash with one another. To show your work as if they are parallel, you can continue the lines down and write a note saying they won't collide or you just say they won't collide and are parallel lines.

6 0
3 years ago
Helpppppppppppppo anyone
Alenkasestr [34]

Answer: 50653

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Step-by-step explanation:

3 0
3 years ago
What is 17.70 = 7/2m + 13.50 ?
Fantom [35]

<u>answer:</u>  m = 1.2

<u>work:</u>

17.70 = \frac{7}{2} m + 13.50  | subtract 13.50 and move it over

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6 0
3 years ago
How do you do this question?
Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\

\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0
3 years ago
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