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4 years ago

Rewrite using powers of ten 32,000,000

Mathematics

2 answers:

butalik [34]4 years ago

8 0

32•10 to the power of 6

mamaluj [8]4 years ago

5 0

32×10×10×10×10×10×10

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Your co-worker, Amanda, and you are reliving your high school athletic "glory days" during a coffee break. She played basketball

topjm [15]

Answer:

Our score = 0.60, Amanda's score = 0.25

Step-by-step explanation:

For Amanda

μ = 15 , σ = 4

z- score for X = 16 is (From z table)

z = (X - μ)/σ = (16 - 15)/4 = 0.25

For us

μ = 310 , σ = 25

z score for X = 325 (From z table)

z = (325-310)/25 = 0.60

Since our z score is better than Amanda's z score, we can say we did better

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4 years ago

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kati45 [8]

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3 years ago

Find the slope using the following two points (19.3) and (20,3)

Sidana [21]

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3 years ago

The wake of each variable. Round your answer to the nearest tenth<br> 15<br> y<br> 45°

Llana [10]

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Step-by-step explanation:depends how your using it

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3 years ago

Compute the standard error for sample proportions from a population with proportion p= 0.55 for sample sizes of n=30, n=100 and

Pani-rosa [81]

Given Information:

Population proportion = p = 0.55

Sample size 1 = n₁ = 30

Sample size 2 = n₂ = 100

Sample size 3 = n₃ = 1000

Required Information:

Standard error = σ = ?

Answer:

$\sigma_1 = 0.091$

$\sigma_2 = 0.050$

$\sigma_3 = 0.016$

Step-by-step explanation:

The standard error for sample proportions from a population is given by

$\sigma = \sqrt{\frac{p(1-p)}{n} }$

Where p is the population proportion and n is the sample size.

For sample size n₁ = 30

$\sigma_1 = \sqrt{\frac{p(1-p)}{n_1} }$

$\sigma_1 = \sqrt{\frac{0.55(1-0.55)}{30} }$

$\sigma_1 = 0.091$

For sample size n₂ = 100

$\sigma_2 = \sqrt{\frac{p(1-p)}{n_2} }$

$\sigma_2 = \sqrt{\frac{0.55(1-0.55)}{100} }$

$\sigma_2 = 0.050$

For sample size n₃ = 1000

$\sigma_3 = \sqrt{\frac{p(1-p)}{n_3} }$

$\sigma_3 = \sqrt{\frac{0.55(1-0.55)}{1000} }$

$\sigma_3 = 0.016$

As you can notice, the standard error decreases as the sample size increases.

Therefore, the greater the sample size lesser will be the standard error.

8 0

4 years ago