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3 years ago

Rewrite using powers of ten 32,000,000

Mathematics

2 answers:

butalik [34]3 years ago

8 0

32•10 to the power of 6

mamaluj [8]3 years ago

5 0

32×10×10×10×10×10×10

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Identify the ordered pair that represents the vector from a(-9,9) to b(7,3) and the magnitude of ab.

sveta [45]

Answer:

Answers below

Step-by-step explanation:

1. Order pair method

[(x2-x1) , (y2-y1)] = b-a = [(7--9) , (3-9)] = (16,-6)

2. Magnitude

|v| = $\sqrt{16^2+-6^2}$

v = |17.088|

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3 years ago

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You scored 31 out of 40 points on a test. What percent did you get?

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

Divide 31 by 40. Since you get .775, you make it a percent and it's 77.5% correct.

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3 years ago

A shirt that normally sells for $28 is on sale at a 10% discount. What is the sale price of the shirt?

sdas [7]

The shirt would then be $25.20

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3 years ago

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The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand

NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in foreign language=0.20

The probability than an American CEO can not transact business in foreign language= $1-0.20=0.80$

Total number of American CEOs chosen=12

a. The probability that none can transact business in a foreign language= $12C_0(0.20)^0(0.80)^{12}$

Using binomial theorem $nC_r(1-p)^{n-r}p^r$

The probability that none can transact business in a foreign language= $\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}$

b.The probability that at least two can transact business in a foreign language= $1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))$

c.The probability that all 12 can transact business in a foreign language= $12C_{12}(0.8)^0(0.2)^{12}$

The probability that all 12 can transact business in a foreign language= $\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}$

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3 years ago

Multiply Conjugates (r+1/4)r-1/4)

Mamont248 [21]

Answer:

$\large\boxed{\left(r+\dfrac{1}{4}\right)\left(r-\dfrac{1}{4}\right)=r^2-\dfrac{1}{16}}$

Step-by-step explanation:

$\text{Use}\ (a+b)(a-b)=a^2-b^2\\\\\left(r+\dfrac{1}{4}\right)\left(r-\dfrac{1}{4}\right)=r^2-\left(\dfrac{1}{4}\right)^2=r^2-\dfrac{1^2}{4^2}=r^2-\dfrac{1}{16}$

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3 years ago

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