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Kruka [31]
3 years ago
13

Instructions: Read the prompt, respond to the prompt below the sources provided. Use the quote and sources provided to support y

our claims and cite your evidence with appropriate citations.
Grade 6 Writing Prompt



In Marjory’s book, The Everglades: River of Grass, she looks at every aspect of the inter-connected Everglades and highlighted its unique beauty and importance. However, many early explorers believed the Everglades to be a flooded wasteland that should be drained. From the perspective of a South Florida pioneer (late 19th century to early 20th century), write an essay to argue for or against the draining and development of the Everglades region. Consider the need for homes, water, food (agriculture), and the presence of indigenous communities in the Everglades.
Mathematics
1 answer:
olga55 [171]3 years ago
6 0

Answer: cool

Step-by-step explanation:

You might be interested in
Consider the function f(x)=xln(x). Let Tn be the nth degree Taylor approximation of f(2) about x=1. Find: T1, T2, T3. find |R3|
Fynjy0 [20]

Answer:

R3 <= 0.083

Step-by-step explanation:

f(x)=xlnx,

The derivatives are as follows:

f'(x)=1+lnx,

f"(x)=1/x,

f"'(x)=-1/x²

f^(4)(x)=2/x³

Simialrly;

f(1) = 0,

f'(1) = 1,

f"(1) = 1,

f"'(1) = -1,

f^(4)(1) = 2

As such;

T1 = f(1) + f'(1)(x-1)

T1 = 0+1(x-1)

T1 = x - 1

T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2

T2 = 0+1(x-1)+1(x-1)^2

T2 = x-1+(x²-2x+1)/2

T2 = x²/2 - 1/2

T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3

T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3

T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)

Thus, T1(2) = 2 - 1

T1(2) = 1

T2 (2) = 2²/2 - 1/2

T2 (2) = 3/2

T2 (2) = 1.5

T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)

T3(2) = 4/3

T3(2) = 1.333

Since;

f(2) = 2 × ln(2)

f(2) = 2×0.693147 =

f(2) = 1.386294

Since;

f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).

Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,

Since;

f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2

Finally;

R3 <= |2/(4!)(2-1)^4|

R3 <= | 2 / 24× 1 |

R3 <= 1/12

R3 <= 0.083

5 0
3 years ago
What is the rate of heat transfer required to melt 1-ton of ice at 32 F in 24 hours?
LiRa [457]

Answer:

3865.74 J/s

Step-by-step explanation:

mass of ice, m = 1 ton = 1000 kg

time , t = 24 hours

latent heat of fusion of ice, L  = 334000 J/kg

Heat required to melt, H = m x L

where, m is the mass of ice and L be the latent heat of fusion

So, H = 1000 x 334000 = 334 xx 10^6 J

Rate of heat transfer = heat / time = \frac{334\times 10^{6}}{86400}

Rate of heat transfer = 3865.74 J/s

thus, the rate of heat transfer is 3865.74 J/s.

8 0
3 years ago
What is the distance between points N and M?
Ira Lisetskai [31]

Answer:

B. 5.8

Step-by-step explanation:

When you do the Pythagorean theorem, you would set 5 as a and 3 as b.

Square both sides and add to get 34

You then take the square root of that to find c which would be 5.8

4 0
2 years ago
Read 2 more answers
Anita text a photo of five Dolphins to a friend to five friends she asked each of her five friends to text the photo to 5 more f
Y_Kistochka [10]
You would multiply 78,125 by 5 and get I think 390,625? I think
7 0
2 years ago
Read 2 more answers
Use the null hypothesis H0 : μ = 98.6, alternative hypothesis Ha: μ &lt; 98.6, and level of significance α = 0.05. 98 99.6 97.8
andrezito [222]

Answer:

The t-score is -1.8432    

Step-by-step explanation:

We are given the following in the question:  

98, 99.6, 97.8, 97.6, 98.7, 98.4, 98.9, 97.1, 99.2, 97.4, 99.1, 96.9, 98.8, 99.9, 96.8, 97, 98.7, 97.6, 98.7, 98.2

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1964.4}{20} = 98.22

Sum of squares of differences = 16.152

s = \sqrt{\dfrac{16.152}{49}} = 0.922

Population mean, μ = 98.6

Sample mean, \bar{x} = 98.22

Sample size, n = 20

Sample standard deviation, s = 0.922

First, we design the null and the alternate hypothesis

H_{0}: \mu = 98.6\\H_A: \mu < 98.6

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{98.22 - 98.6}{\frac{0.922}{\sqrt{20}} } = -1.8432

The t-score is -1.8432    

7 0
3 years ago
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