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4 years ago

A+8+A=18 2A+3B=46 B+7+C=27 A+2B+3C=?

Mathematics

1 answer:

ycow [4]4 years ago

6 0

Answer:

Step-by-step explanation:

A=5

B=10+3B=46

B=12

C= 12+7+C= 27

C=8

fourth equation

5+24+24

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2 years ago

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Bingel [31]

Answer:

$\theta=251.6^\circ$

Step-by-step explanation:

<u>Complex Numbers</u>

They are expressed as the sum of a real part and an imaginary part:

$Z = a+b\mathbf{ i}$

Complex numbers can also be expressed in polar form:

$Z = r(\cos\theta+\sin\theta \mathbf{ i}) = r. cis(\theta)$

Where r is the modulus of the complex number and θ is the argument.

The argument can be calculated by:

$\displaystyle \tan\theta=\frac{b}{a}$

The angle θ must be calculated in the appropriate quadrant depending on the signs of the real and imaginary parts.

The complex number is given as:

$Z = -3 -9\mathbf{ i}$

Here: a=-3, b=-9

Since both components are negative, the argument lies in the third quadrant (180° < θ < 270°).

$\displaystyle \tan\theta=\frac{-9}{-3}$

$\displaystyle \tan\theta=3$

$\theta=\arctan(3)$

The calculator gives the answer 71.6°, we need to adjust the angle to the third quadrant by adding 180°, thus

$\mathbf{\theta=251.6^\circ}$

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