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stepan [7]
1 year ago
6

PLEASE HELP ASAP 30 POINTS!

Mathematics
2 answers:
Zarrin [17]1 year ago
7 0

Answer:-4/3

Step-by-step explanation:

sveta [45]1 year ago
6 0

Answer:

-4/3

Step-by-step explanation:

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Select the correct answer.<br> Which function is the inverse of function<br> f(x) = -2
Artemon [7]

Answer:

B

Step-by-step explanation:

let f(x) = y and rearrange making x the subject

y = \frac{x+2}{7} ( multiply both sides by 7 to clear the fraction )

7y = x + 2 ( subtract 2 from both sides )

7y - 2 = x

Change y back into terms of x with x the inverse function, that is

p(x) = 7x - 2

8 0
3 years ago
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Find the area of quadrilateral ABCD
LenaWriter [7]

Answer:

it can be solved using the formula hope it will hep you

3 0
3 years ago
5. Janna and Laura broke a six-inch candy bar in half to share with each
kobusy [5.1K]

Answer:

3 inches

Step-by-step explanation:

6 divded by 2 (or in half ) is 3

4 0
3 years ago
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(6x −9)3−1=((6x−9)3)(0) Solve for X
Tasya [4]

Answer:

Step-by-step explanation:

Remark

Anything multiplied by 0 = 0. So the whole right side is 0.

(6x - 9)*3 - 1  = 0                       Add 1 to both sides.

(6x - 9)*3 - 1 + 1 = 0 + 1             Combine

(6x - 9)*3 = 1                             Divide both sides by 3

(6x - 9)*3/3 = 1/3                      Simplify

(6x - 9) = 1/3                             Remove brackets. Add 9 to both sides

6x - 9+9 = 9 1/3                        Combine

6x = 9 1/3

6x = 28/3                                   Divide both sides by 6

6x / 6 = 28/3 // 6                       Invert the 6 and multiply.

x = 28/3 * 1/6

x = 28/18

Answer

x = 14/9

6 0
2 years ago
Drag the tiles to the correct boxes to complete the palrs.
Brut [27]

Answer:

(f+g)(2)  = 4

(f-g)(4) = 8

(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

f(x) = 2x + 3

g(x) = x - 1

(f+g)(2)

(f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2

At x = 2

(f+g)(2) = 3(2) - 2 = 6 - 2 = 4

Then

(f+g)(2)  = 4

(f-g)(4)

(f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4

At x = 4

(f-g)(4) = 4 + 4 = 8

Then

(f-g)(4) = 8

(f ÷g)(2)

(f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}

At x = 2

(f \div g)(2) = \frac{7}{1} = 7

Then

(f ÷g)(2) = 7

(f x g)(1)

(f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3

Then

(f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0

So

(f x g)(1) = 0

4 0
3 years ago
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