Using the recurrence relation, we can find a couple more values in the sequence:
- a3 = 3a2 -3a1 +a0 = 3(4) -3(2) +2 = 8
- a4 = 3a3 -3a2 +a1 = 3(8) -3(4) +2 = 14
First differences are 0, 2, 4, 6, ...
Second differences are constant at 2, so the function is quadratic.
The sequence can be described by the quadratic ...
... an = n² -n +2
_____
We know the value for n=0 is 2, so we can find <em>a</em> and <em>b</em> using the given values for a1 and a2.
... an = an² +bn +2
... a1 = 2 = a·1² +b·1 +2 . . . . for n=1
... a + b = 0
... a2 = 4 = a·2² -a·2 +2 . . . . for n = 2; using b=-a from the previous equation
... 2 = 2a
... a = 1 . . . . so b = -1
First, let's find the area of one face of the cube.
Area = base x height
A = 5 x 5 = 25
There are 6 faces on a cube, so we can multiply the area of one face by 6 to get the total surface area.
SA = 25 x 6 = 150 ft^2
Hope this helps!
Median = 75 because that is where the middle line of the box is.
First quartile = 70 because that is what the left edge of the box represents.
Third quartile = 85 because the right edge of the box indicates that.
Maximum = 100 because at the far right is the maximum data point of your data set.
The middle 50% of that data is between 70 and 85 because those are the values the box covers. It goes from the first quartile, 70, and stretches all the way to the third quartile 85.
Answer:
40%
Step-by-step explanation:
Subtract 1,400 by 1,000 then divide by 1,000
