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3 years ago

5

Mathematics

1 answer:

Leto [7]3 years ago

3 0

Answer:

False.

Step-by-step explanation:

If we substitute a for 6, the inequality would become 6 > 6. That is not true because 6 cannot be greater than itself.

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a jar contains 133 pennies. a bigger jar contains 1 2/7 times as many pennies. what is the value of the pennies in the bigger ja

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$Multiply\ 1\frac{2}{7}\ times\ pennies\ in\ jar\\\\
 1\frac{2}{7}*133=\frac{9}{7}*133=\frac{1197}{7}=171\\\\
In\ the\ bigger\ jar\ there\ are\ 171\ pennies.$

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IRISSAK [1]

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Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north

Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

$x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]$

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

Child 1 final position => $x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t$
Child 2 final position => $x_{2f} =0+v_{2} t$

4) Sum the equations and equate to 3

$x_{1f} +x_{2f} =3$

5) Substitute the values we already know

$1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]$

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

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3 years ago