To solve the exercirses which are shown in the figure attached, you must follow the proccedure below:
7) (x)=x³-6x²+8x
(x)=x(x³-6x²+8)
(x)=(x-4)(x-2)x
The lenght is: x
The height is= (x-4)
8) √(2x+8)-6=4
1. You need to clear the variable "x". Then:
√(2x+8)=4+6
√(2x+8)=10
(√2x+8)²=10²
2x+8=100
2x=100-8
x=92/2
x=46
9) l4x+3l=9+2x
1. To solve the left member, you must evaluate two cases: it could be positive,or negative. Then:
2. Negative:
l4x+3l=9+2x
-4x-3=9+2x
-4x-2x=9+3
-6x=12
x=12/-6
x=-2
3. Positive:
l4x+3l=9+2x
4x+3=9+2x
4x-2x=9-3
2x=6
x=6/2
x=3
<span>
Based on the rules of statistics</span>
68% of the data falls within 1 standard deviation of the mean
95% of the data falls within 2 standard deviation of the mean
99% of the data falls within 3 standard deviation of the mean
20 falls between the range of -56 to 56 (from the given 95%)
Hence we accept the null hypothesis; else, if the mean falls outside the
range, we reject the null hypothesis.
<span> </span>
Answer:
50 = 2
Step-by-step explanation:
which by definition equates to 68+1
Answer:
10 units
Step-by-step explanation:
Given data
P = (3, 1) and Q = (-3, -7)
x1=3
y1=1
x2= -3
y2= -7
The expression for the distance between two coordinate is
d=√((x_2-x_1)²+(y_2-y_1)²)
Substitute
d=√((-3-3)²+(-7-1)²)
d=√((-6)²+(-8)²)
d=√36+64
d=√100
d=10 units
Hence the distance is 10 units
To find the probability of landing on a triangle, you will want find the combined areas of the triangles and the total area of the square target.
Divide the area of the combined areas and the total area to find the probability of landing on a triangle.
A = 1/2bh
1/2 x 8 x 8
A = 32 square inches
32 x 4
128 square inches (areas of triangles)
A = bh
26 x 26
A = 676 square inches
128/676 = 0.189
There is an approximate probability of 0.19 of hitting a triangle.
