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3 years ago

James goal is is to earn at least $80 towards a week at soccer camp. He has earned $32 so far. How much more does

2 answers:

6 0

Answer:

$48

Step-By-Step Explanation:

Since your trying to figure out have much more money he needs, you’ll need to subtract the money he has so far and the goal.

80 - 32 = $48

cupoosta [38]3 years ago

4 0

He needs to earn $48

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Expand and simplify (2x−12) ^2

lubasha [3.4K]

Answer:

$\boxed{4x^{2} - 48x + 144}$

Step-by-step explanation:

Given expression:

(2x - 12)²

To simplify the expression, we will use the formula (a - b)² = a² - 2ab + b².

[Where "a and b" are the first and second term in (a - b)²]

$\rightarrowtail (2x - 12)^{2}$

In this case, the first term of (2x - 12)² is "2x" and the second term is "12".

$\rightarrowtail (2x)^{2} - 2(2x)(12) + (12)^{2} \ \ \ \ \ \ \ \ \ \ \ \ \ \ [\small\text{First term = a = 2x; Second term = b = 12]}$

Now, simplify the expression.

$\rightarrowtail (2x)^{2} - 2(2x)(12) + (12)^{2}$

$\rightarrowtail (2x)(2x) - (4x)(12) + (12)(12)$

$\rightarrowtail \boxed{4x^{2} - 48x + 144}$

4 0

2 years ago

Solve for y. 9x+5y=7 <br>

Yuliya22 [10]

Answer: y=7/5-9x/5

Step-by-step explanation:

im sorry if this dont help

5 0

3 years ago

Read 2 more answers

What is the product?

ra1l [238]

-9x(5 - 2x) Distribute/multiply 9x into (5 - 2x)

(-9x)5 - (-9x)2x

-45x - (-18x²) 2 negative signs cancel each other out and become +

-45x + 18x² Your answer is A ( the first option)

3 0

3 years ago

Evaluate

Annette [7]

Answer:

=0.000342

Standard form is 3.4237×10 ${}^{-4}$

Step-by-step explanation:

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8 0

2 years ago

The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Artemon [7]

Answer:

P(X $\geq$ 74) = 0.3707

Step-by-step explanation:

We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Let X = Score of golfers

So, X ~ N( $\mu=73,\sigma^{2}=3^{2}$ )

The z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 73

$\sigma$ = standard deviation = 3

So, the probability that the score of golfer is at least 74 is given by = P(X $\geq$ 74)

P(X $\geq$ 74) = P( $\frac{X-\mu}{\sigma}$ $\geq$ $\frac{74-73}{3}$ ) = P(Z $\geq$ 0.33) = 1 - P(Z < 0.33)

= 1 - 0.62930 = 0.3707

Therefore, the probability that the score of golfer is at least 74 is 0.3707 .

3 0

3 years ago