Hello,
As
=π/6+2kπ or -π/6+2kπ
As
=π/6+2kπ or -π/6+2kπ
3. Compare corresponding sides that include the
1 answer:
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The customer can purchase 1.19788 pounds of cheese (approximately 1.2 pounds).
<h3>How much cheese can she purchase?</h3>We are given with the cost of ham is $2.49 per pound and
Cost of swiss cheese is $3.79 per pound.
So, the cost of 2 pounds of ham will be given as-
= 2× $2.49
= $4.98
Since, the customer has a total of $9.50 to spend on 2 pounds of ham and some cheese,
∴ Let the number of pounds of cheese she can purchase be x.
Then the equation will be this:
2.49*2 + 3.79*x = 9.50
4.98 + 3.79x = 9.50
Subtracting 4.98 from each side we get-
4.98 -4.98 + 3.79x = 9.50-4.98
3.79x = 4.54
x
x = 1.19788 pounds of cheese (approximately 1.2 pounds).
Hence, the customer can purchase 1.19788 pounds of cheese (approximately 1.2 pounds).
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To solve this problem, set up and solve a system of equations. The variables b and m will represent a bread loaf and milk jug, respectively:
I would solve using substitution. Take one of the equations and set it equal to one of the variables, for example:
Now, plug this into the other equation for m and solve for b:
We now know that a loaf of bread costs $2.50. Plug this value in for b in the first equation and solve for m:
One jug of milk costs $1.50 and one loaf of bread costs $2.50.
I would solve using substitution. Take one of the equations and set it equal to one of the variables, for example:
Now, plug this into the other equation for m and solve for b:
We now know that a loaf of bread costs $2.50. Plug this value in for b in the first equation and solve for m:
One jug of milk costs $1.50 and one loaf of bread costs $2.50.