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irina [24]
3 years ago
13

Greatest common factor 84 and 100

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
5 0

Answer:

4

Step-by-step explanation:

The factors of 84 are: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84

The factors of 100 are: 1, 2, 4, 5, 10, 20, 25, 50, 100

They have 4 in common

harina [27]3 years ago
4 0

Answer:

4

Step-by-step explanation:

100 = 2*2*5*5

84 = 2*2*3*4

the greatest common factor is a prime number whit most appearance in both numbers:

in this case the prime number is 2 and it is repeated twice in both numbers, hence 2*2 = 4

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The sum of nine times a number and five is one hundred eighty-five
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9 x (x +5) = 185

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I'm pretty sure this is how you write it

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Mount Everest is 8,850m tall. Convert the height to kilometers.
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Answer: 8.85km

Step-by-step explanation:

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6 0
3 years ago
Anyone know the answer ?
Likurg_2 [28]

Answer:   see where the two lines intercept and when you get the answer, look to see which region is is the closest to the answer but if you look closer region A is closer plus open/Search a graph and put y>-x in the first box and put y<x-2 in second box  to see where is intercept at the you get your answer, but region A is the answer you do need.

Step-by-step explanation:

6 0
3 years ago
A piece of cardboard is 13 inches by 26 inches. A square is to be cut from each corner and the sides folded up to make an open-t
Vanyuwa [196]

Answer:

Hence the maximum possible volume will be the 778.53 c.c

Step-by-step explanation:

Given:

A rectangle with 13 x 26 dimensions

And corners are cut to form side squares.

To Find:

Maximum possible volume for box

Solution :

Consider a rectangle of 13 x 26 dimension with and side of square  at corner be x.

(Refer the attachment)

Now,

Formulating the volume equation for the box

So corner square sides we are going to fold up which makes height of the box

and remaining part will be length and breadth

As shown in fig,

Length=26-x

breadth=13-x

And height will be x

V(x)=x*(26-x)*(13-x)

To get maximum volume differentiate the above equation,

V(x)=x*(26*13-26*x-13*x+x^2)

V(x)=x^3-39x^2+338x\\

V'(x)=3x^2-78x+338

V''(x)=6x-78

Now ,Solve the Quadratic Equation to get x values,

3x^2-78x+338=0

x=[-b±(b^2-4ac)^1/2]/2a

x=[78±Sqrt[(78)^2-4*338*3)]/2*3

x=[78±Sqrt(3028)]/6

x=[78±55.027]/6

x=78+55.027/6 or x=78-55.027/6

x=22.17  or x=3.8288

Use these values in 6x-78 to know which value posses the max and min value for the function.

So when x=22.17

6x-78=6*22.17-78

=55.02>0  i.e function will have minimum value .

When x=3.8288

6*3.8288-78

=-55.0272<0 i.e. Function will have maximum value

Now, the function will defines the maximum volume

V(x)=x^3-39x^2+338x

V(x)=3.8288^3-39*(3.82883)^2+338*3.8288

V(x)=56.13-571.73+1294.13

V(x)=778.53 C.C

6 0
3 years ago
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