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irina [24]
3 years ago
13

Greatest common factor 84 and 100

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
5 0

Answer:

4

Step-by-step explanation:

The factors of 84 are: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84

The factors of 100 are: 1, 2, 4, 5, 10, 20, 25, 50, 100

They have 4 in common

harina [27]3 years ago
4 0

Answer:

4

Step-by-step explanation:

100 = 2*2*5*5

84 = 2*2*3*4

the greatest common factor is a prime number whit most appearance in both numbers:

in this case the prime number is 2 and it is repeated twice in both numbers, hence 2*2 = 4

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Is this problem right because I need to know thanks!!
inna [77]

Sadly, the answer to your question is 'No'.  The work written under
the problem on the paper is not correct ... because you tried to do
too much !

You can't combine 'm' terms with 'n' terms or with plain numbers.
They all need to stay separate all the way to the end.

So, actually, your first written line is the answer . . .  <em>7m - 35 + 3n</em>

That's as far as you can go.  You can't combine these terms. Stop there !


8 0
4 years ago
Can you please help me ASAP
creativ13 [48]

Answer:43 will be 2311. 45 is Translition. 46 is 2049.9001. 47 is g(322)=301 x-3 is a 3499

Step-by-step explanation:

3 0
2 years ago
Samantha is making some floral arrangements.The table shows the prices for packs of six of each type of flower.
belka [17]
Okay so the first thing we should do here is round 5.29 rounds to 5.30 3.59 rounds to 3.60 and 4.79 rounds to 4.80 now add all of those up youll get 13.7 you can round that to 14 so samanthas estimate is accurate
4 0
3 years ago
Let m=6x+5m=6x+5m, equals, 6, x, plus, 5.
KATRIN_1 [288]

We have been given that m=6x+5. We are asked to rewrite the equation (6x+5)^2-10=-18x-15 in terms of m.

First of all, we need manipulate right side of our given equation.

We will factor out -3 from right side of equation as:

(6x+5)^2-10=-3(6x+5)

Upon substituting m=6x+5 in our equation, we will get:

(m)^2-10=-3(m)

m^2-10=-3m

Upon writing this equation in general form of equation, we will get:

m^2+3m-10=-3m+3m

m^2+3m-10=0

Therefore, the equation m^2+3m-10=0 is equivalent to our given equation.

4 0
4 years ago
sarah has $400 in her saving account and she has to pay $15 each month to her parents for her cell phone. draius has $50 and he
soldi70 [24.7K]
For this question, personally, I would do it algebraically.

So set m to the number of months until they will have the same amount of money. Then you can write an equation matching this scenario, and solve for m as well.

So first, write the side of the equation for Sarah.

She originally had $400, and each month pays $15.

So 400 - 15m for subtracting how much she pays in total, 15m, from her total amount of money, $400.

Now, write the side of the equation for Draius. 

He originally had $50, and he gets $20 each month.

So the equation would be 50 + 20m, for how much he gets in total adding to $50.

Now set the two equal.

400 - 15m = 50 + 20m

Now, move all like terms to opposite sides by using opposite operations.

Subtract 50 from both sides:

400 - 50 - 15m = 50 - 50 + 20m
350 - 15m = 20m

Now add 15m to both sides.

350 - 15m + 15m = 20m + 15m

350 = 35m

Divide both sides by 35:

350/35 = 35m/35

m = 10

So Sarah and Darius will have the same amount of money in 10 months.

Now you can plug 10 into the equation to find out how much money they both have.

I'll just plug it in for 400 - 15m:

400 - 15 (10)
= 400 - 150
= 250

And since they'll both have the same amount of money, they'll both have $250. 
5 0
4 years ago
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