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MariettaO [177]
3 years ago
13

The train travels 120 miles in 2 hours. How far will the train travel in 4 hours?

Mathematics
2 answers:
sweet [91]3 years ago
7 0
120 miles - 2 hours
x miles - 4 hours
cross multiply:
2x=4 \times 120 \\
2x=480 \\
x=\frac{480}{2} \\
x=240

It will travel 240 miles.
Hoochie [10]3 years ago
4 0
So 120/2 and x/4 p.s it can also be written 120/x = 2/4 depending on which way you like to solve proportions. Cross multiply 4· 120= 480 and 2·X= 2x Divide 480 by 2 and x= 240
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Find the value of b in the graph of y=3x+b if it is known that the graph goes through the point: N(0,5)
tino4ka555 [31]

Answer:

I believe b is 5.

Step-by-step explanation:

When you place the points in the values, you get 5=3(0)+b. When you simplify it, you get 5=b. I really hope this is correct, I apologize if it isn't! I hope this helps! :)

4 0
4 years ago
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V(t), left parenthesis, t, right parenthesis models the number of visitors in a park as a function of the outside temperature t
Kruka [31]

Answer:

The number of visitors increases at the same rate over both intervals

Step-by-step explanation:

The unit rate at which the number of visitors in the park increases over a given temperature interval is called the average rate of change, or ARCARCA, R, C.

To find the average rate of change of a function over an interval, we need to take the total change in the function value over the interval and divide it by the length of the interval.

Hint #22 / 3

We are asked to compare the rates at which the number of visitors increases over the interval between an outside temperature of 181818 degrees Celsius and 202020 degrees Celsius, and over the interval between an outside temperature of 202020 degrees Celsius and 272727 degrees Celsius. These correspond to the domain intervals [18,20][18,20]open bracket, 18, comma, 20, close bracket and [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Let's calculate the average rate of change of VVV over those intervals:

ARC_{[18,20]}ARC

[18,20]

​

A, R, C, start subscript, open bracket, 18, comma, 20, close bracket, end subscript ARC_{[20,27]}ARC

[20,27]

​

A, R, C, start subscript, open bracket, 20, comma, 27, close bracket, end subscript

\begin{aligned} \dfrac{V(20)-V(18)}{20-18}&=\dfrac{18-10}{2}\\\\&=\dfrac{8}{2}\\\\&=4\end{aligned}\quad

20−18

V(20)−V(18)

​

​

 

=

2

18−10

​

=

2

8

​

=4

​

 \begin{aligned} \dfrac{V(27)-V(20)}{27-20}&=\dfrac{46-18}{7}\\\\&=\dfrac{28}{7}\\\\&=4\end{aligned}

27−20

V(27)−V(20)

​

​

 

=

7

46−18

​

=

7

28

​

=4

​

Hint #33 / 3

The average rate of change over the interval [18,20][18,20]open bracket, 18, comma, 20, close bracket is the same as the average rate of change over the interval [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Therefore, the number of visitors increases at the same rate over both intervals.

7 0
3 years ago
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malfutka [58]

Answer:

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Step-by-step explanation:

80+50= 130

180-130=50

180-50=130°

3 0
3 years ago
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tensa zangetsu [6.8K]
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3/1.80 = x/100

Cross multiply and solve for x.

300 = 1.8x

x = 166.67%
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Answer:

6.96 (ROUNDED ANSWER)

Step-by-step explanation:

SQUARE ROOT OF 4 = 2.64

2.64 ²=6.96

7 0
2 years ago
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